All categories

4 years ago

Divide £56 in a ratio of 5:3

Mathematics

1 answer:

uysha [10]4 years ago

4 0

£56 = 5+3
= 8
£7 = 1

5= £7 x 5 = £35
3= £7 x 3 = £21

Do you mean like this?

You might be interested in

What is the solution to -3a-4

Aleksandr-060686 [28]

Answer:

answer is 7a proved

Step-by-step explanation:

sloution

=-3a-4

=-+- =+ so,

=-3a-4

=7a

mark me as brainlist

8 0

3 years ago

What is the value for y? Enter your answer in the box. y = An isosceles triangle A B C with horizontal base B C and vertex A is

vfiekz [6]

Answer:

x = 25

y = 14

Explanation:

The described scenario can be represented using the attached triangle.

1- getting the value of x:

We know that ΔABC is an isosceles triangle with AC = BC

This means that:

∠CAB = ∠CBA

We know that ∠CAB = 50° and ∠CBA = 2x°

Equating the two angles, we get:

50 = 2x .................> Divide both sides by 2

x = 25

2- getting the value of y:

We know that the sum of the internal angles of a triangle is 180°

This means that:

∠ABC + ∠CAB + ∠ACB = 180°

We have:

∠ABC = 2x = 50°

∠ACB = 5y + 10

∠CAB = 50°

Now, we substitute to get the value of y as follows:

50 + 50 + 5y + 10 = 180

110 + 5y = 180

5y = 180 - 110

5y = 70 .............> Divide both sides by 5

y = 14

Hope this helps :)

7 0

3 years ago

I NEED HELP PLEASE HELP ME

zavuch27 [327]

We will use the Pythagora’s theorem for this. Using the formula: a^2 + b^2 = c^2
Pls see the below working out :)

3 0

3 years ago

Read 2 more answers

Please help! i’ll give brainliest! thank u!

Ivenika [448]

Answer:

Negative with little correlation

It has negative slope if you imagine a line

8 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago