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Black_prince [1.1K]
3 years ago
5

Input an int between 0 and 100 and print the numbers between it and 100, including the number itself and the number 100. If the

number is less than or equal to 0, or greater than or equal to 100 print "error". Print 20 numbers per line.
Language: Java
Computers and Technology
1 answer:
Murrr4er [49]3 years ago
6 0

import java.util.Scanner;

public class JavaApplication42 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       int count = 0;

       System.out.println("Enter an integer between 0 and 100");

       int num = scan.nextInt();

       if (num <= 0 || num >= 100){

           System.out.println("error");

       }

       else{

           while(num <= 100){

               if (count == 20){

                   System.out.println("");

                   count = 0;

               }

               else{

                   System.out.print(num+" ");

                   count++;

                   num++;

               }

           }

       }

   }

   

}

I hope this helps!

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The program to this question can be described as follows:

Program:

#include <stdio.h> //defining header file  

int main() //defining main method

{

int* numItemsPointer; //defining pointer variable

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