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Brut [27]
3 years ago
11

Please help with math

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

Answer:

First, third, and fourth one would be the answers.

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Y=-2/3x+3 please show the work thank you ;)
Ivahew [28]

Answer:

Step-by-step explanation:

Looking at y=-%282%2F3%29x%2B3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-2%2F3 and the y-intercept is b=3

Since b=3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

slope=rise%2Frun

Also, because the slope is -2%2F3, this means:

rise%2Frun=-2%2F3

which shows us that the rise is -2 and the run is 3. This means that to go from point to point, we can go down 2 and over 3

So starting at , go down 2 units

and to the right 3 units to get to the next point

Now draw a line through these points to graph y=-%282%2F3%29x%2B3

So this is the graph of y=-%282%2F3%29x%2B3 through the points  and

3 0
3 years ago
If x is 5 what is the value of 4x?
Bond [772]

Answer:

The answer is 20

Step-by-step explanation:

This is because 4(5)= 20

Hope this helps :)

7 0
3 years ago
Read 2 more answers
Find the zeros of the following equation using the quadratic formula y = x2 + 13x – 48​
Art [367]
X2+13x-48
(x-3)(x+16)
X=3, X=-16
3 and -16 are the Zeros
5 0
3 years ago
Henry steps onto an elevator at the first floor. He goes up to the 9th floor and then comes down 2 floors. He then goes up 4 flo
dimaraw [331]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
What is the first and second derivative of xe^(2x)?
Nimfa-mama [501]
f(x)=xe^{2x}\\\\f'(x)=x'e^{2x}+x(e^{2x})'=e^{2x}+xe^{2x}\cdot2=2xe^{2x}+e^{2x}=e^{2x}(2x+1)\\\\f''(x)=(e^{2x})'(2x+1)+e^{2x}(2x+1)'=e^{2x}\cdot2(2x+1)+e^{2x}\cdot2\\\\=e^{2x}(4x+2)+2e^{2x}=(4x+2+2)e^{2x}=(4x+4)e^{2x}\\\\Answer:\\\boxed{f'(x)=(2x+1)e^{2x}\ and\ f''(x)=(4x+4)e^{2x}}
5 0
3 years ago
Read 2 more answers
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