Answer:
The value of change in internal l energy of the gas = 1850 J
Explanation:
Work done on the gas (W) = - 1850 J
Negative sign is due to work done on the system.
From the first law we know that Q = Δ U + W ------------- (1)
Where Q = Heat transfer to the gas
Δ U = Change in internal energy of the gas
W = work done on the gas
Since it is adiabatic compression of the gas so heat transfer to the gas is zero.
⇒ Q = 0
So from equation (1)
⇒ Δ U = - W ----------------- (2)
⇒ W = - 1850 J (Given)
⇒ Δ U = - (- 1850)
⇒ Δ U = + 1850 J
This is the value of change in internal energy of the gas.
If it's volume changes when you move it to the new container it would be a solid
Answer:
Explanation:
easy way
when system is all kinetic energy, velocity is at a maximum
E = ½mv²
v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s
harder way
ω = √(k/m) = √(80/0.5) = √160 rad/s
When the system is entirely spring potential, the amplitude A is
E = ½kA²
A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m
maximum velocity is ωΑ = 0.79√160 = 10 m/s
Answer:
100 g
Explanation:
Let the mass of density 1.2 g/cm³ be x gram and let the mass of density 1.8 g/cm³ be y gram
Applying
Density (D) = mass(m)/Volume (V)
Volume (V) = mass(m)/Density(D)
V = m/D........................... Equation 1
From the question,
x+y = 400...................... Equation 1
Volume of the liquidis
V = 400/1.6 = 250 cm³
(x/1.2)+(y/1.8) = 250
(1.8x/1.2)+y = 450............... Equation 1
Solving both equation simultaneously,
Subtract equation 1 from equation 2
x-(1.8x/1.2)+(y-y) = 400-450
x-1.5x = -50
-0.5x = -50
x = -50/-0.5
x = 100 g.
Hence the mass of the liquid of density 1.2 g/cm³ is 100 g