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3 years ago

KFC has engineered chickens that do not have beaks and double breast

1 answer:

6 0

I don't think so.

Before I can accept that rumor, I'll need to see the signed testimony of
two reputable adult witnesses, who have no connection to any business
that profits in any way from the production, sale, or consumption of food,
and who will swear in a public meeting, presided over by three respected
members of their community, that they personally saw more than one of
the alleged beakless double-breasted chickens in the same place at the
same time.

A photo is not acceptable ... not for me, and not for the two witnesses.

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How do you find the period

Svet_ta [14]

Period is seconds/cycle. So just divide number of seconds by the cycles completed. Hope this helps!

3 0

3 years ago

Exercising in hot weather can cause what side effects ?

trapecia [35]

Answer:

dehydration, lots of sweating, heat stroke, heat exhaustion: nausea, dizziness, vomitting, diahreaa, headache

Explanation:

4 0

3 years ago

Read 2 more answers

HELP ASAP TIMED TEST

balu736 [363]

Answer:

<em>Correct choice: b 4H</em>

Explanation:

<u>Conservation of the mechanical energy</u>

The mechanical energy is the sum of the gravitational potential energy GPE (U) and the kinetic energy KE (K):

E = U + K

The GPE is calculated as:

U = mgh

And the kinetic energy is:

$\displaystyle K=\frac{1}{2}mv^2$

Where:

m = mass of the object

g = gravitational acceleration

h = height of the object

v = speed at which the object moves

When the snowball is dropped from a height H, it has zero speed and therefore zero kinetic energy, thus the mechanical energy is:

$U_1 = mgH$

When the snowball reaches the ground, the height is zero and the GPE is also zero, thus the mechanical energy is:

$\displaystyle U_2=\frac{1}{2}mv^2$

Since the energy is conserved, U1=U2

$\displaystyle mgH=\frac{1}{2}mv^2 \qquad\qquad [1]$

For the speed to be double, we need to drop the snowball from a height H', and:

$\displaystyle mgH'=\frac{1}{2}m(2v)^2$

Operating:

$\displaystyle mgH'=4\frac{1}{2}m(v)^2 \qquad\qquad [2]$

Dividing [2] by [1]

$\displaystyle \frac{mgH'}{mgH}=\frac{4\frac{1}{2}m(v)^2}{\frac{1}{2}m(v)^2}$

Simplifying:

$\displaystyle \frac{H'}{H}=4$

Thus:

H' = 4H

Correct choice: b 4H

4 0

2 years ago

I meed help with these 2 questions plz

ludmilkaskok [199]

-- 30N

-- the sum of all the forces

4 0

3 years ago

During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.

aalyn [17]

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

<h3>What is anomalous expansion of water?</h3>

Anomalous expansion of water is a property of water in which water expands instead of contracting.

Anomalous expansion of water makes water less dense.
The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.

Learn more about properties of water:

brainly.com/question/18681949

4 0

1 year ago