A coconut is attached to a palm
1 answer:
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Answer:
The velocity of water at the bottom,
Given:
Height of water in the tank, h = 12.8 m
Gauge pressure of water,
Solution:
Now,
Atmospheric pressue,
At the top, the absolute pressure,
Now, the pressure at the bottom will be equal to the atmopheric pressure,
The velocity at the top, , l;et the bottom velocity, be
.
Now, by Bernoulli's eqn:
where
Density of sea water,
Answer:
the distance travelled from the bullet to the target is 391m
Explanation:
Hello! To solve this exercise we must follow the following steps.
1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation
X=(V1)(T1)
where
X=target distance
V1=bullet speed=460m/s
T1=
time it takes for the bullet to reach the target
2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)
X=(V2)(T2)
X=
target distance
V2= speed of sound=340m/s
T2= time it takes the sound of the Bullet to return.
3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation
T=T1+T2
2=T1+T2
4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.
the distance travelled from the bullet to the target is 391m