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Rus_ich [418]
3 years ago
10

A coconut is attached to a palm

Physics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

1.22kg

Explanation:

info given:

height (h) = 7.25m

g = 9.81m/s^2

PE = mgh

Plug in info and solve for m.

m(9.81m/s^2)(7.25m) = 87.4J

m = 1.22kg

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For each of the problems below, you will need to draw a graph to find the solution.
Gelneren [198K]

Answer:

Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Explanation:

3 0
2 years ago
A plane passes over Point A with a velocity of 8000 m/s north. Forty seconds later it passes over Point B at a velocity of 10,00
Airida [17]

Answer:

The planes’ acceleration from A to B is 500m/s^2

Explanation:

Given that the initial velocity u is 8000m/s

and also given the final velocity v=10,000 m/s

the time taken to move from A to B = 40 second

The acceleration is defined as the rate of change of velocity with time

we know that the expression for acceleration is given as

a=(v-u)/t

substituting our given data into the expression for a we have

a=(10000-8000)/40

a=2000/40

a=500m/s^2

The planes’ acceleration from A to B is 500m/s^2

7 0
3 years ago
Two astronauts are floating close to each other in space. Can they talk to each other without using any special device? plsss he
storchak [24]

Answer:

no they can't talk to each other bcoz of the lack of atmosphere.

Explanation:

l hope it helps you

5 0
3 years ago
In the chemical formula for an ionic compound, which item is written first?
tatuchka [14]

Explanation:

C,

.hahxxjdndjdndjgfndkndidjdodnxondos

5 0
2 years ago
A piano tuner is using a 392 Hz tuning fork to tune the wire for a G-Natural note. She hears 4 beats per second. What are the tw
inysia [295]

A beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies. Frequency beat is equal to,

f_{beat} =| f_2\pm f_1 |

The reference frequency in our case would be 392Hz, and since there is the possibility of the upper and lower range for the amount of beats per second that the two possible frequencies are heard would be

f_{beat} =|392+4|= 396Hz

f_{beat} =|392-4|=388Hz

Therefore the two possible frequencies the piano wire is vibrating at, would be 396Hz and 388Hz

5 0
3 years ago
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