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Klio2033 [76]
3 years ago
9

Finish this sentence to describe whar happens ro potential energy: as the height of an object increases

Physics
2 answers:
icang [17]3 years ago
7 0

Answer:the potential energy increases

Explanation:

Potential energy is directly proportional to height,as height increases potential energy also increase

Vlad1618 [11]3 years ago
6 0

Answer:

...as the height of an object increases, gravitational potential energy also increases

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Which activity is a model of thermal energy transfer by conduction? A. Freezing ice cubes in a freezer B. Using a heat lamp to w
Ne4ueva [31]

Answer:

Hot water rises and cold water sinks is a model of thermal energy transfer by conduction.

3 0
3 years ago
Read 2 more answers
Suppose a piano tuner hears 2 beats per second when listening to the combined sound from her tuning fork and the piano note bein
maksim [4K]

Answer:

further tightening is required.

Explanation:

The beat created / sec = difference of frequencies

Initial beat heard = 2

so difference of frequencies = 2

after tightening beat heard  = 1

difference  of frequencies decreases because frequency of tuning fork was higher than piano sound.

on further tightening  difference decreases because tightening increases the frequency  of piano hence   further  tightening is required for resonance.

6 0
3 years ago
Particles q1, q2, and q3 are in a straight line.
natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0
1 year ago
does the solar system consist of small planets orbiting close to sun, and larger ones on more further away to the sun.. why?
Akimi4 [234]

Answer:

No

Explanation:

Because Jupiter, the largest planet in the SS, is right in the middle, and moons like Titan are in the very middle, so it's basically small, then huge, and normal again.

8 0
3 years ago
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 30 m/s when i
Semmy [17]
Missing question in the text. Found on internet:
"<span>What was its speed when its height was half that of its starting point?"

Solution:
we can solve the problem by using the law of conservation of energy.

At ground level (let's label this point as point A), the roller coaster has only kinetic energy (because its height is zero, so its potential energy is zero as well), which is
</span>E_A=K_A =  \frac{1}{2} mv_A^2
<span>where m is the mass of the roller coaster and vA is its speed at ground level.

When the roller coaster is at half of the starting height, it has both kinetic energy and potential energy:
</span>E_B = K_B+U_B =  \frac{1}{2}mv_B^2 + mg \frac{h}{2}
where h is the initial height at the starting point.

Since the energy must be conserved, we can write
E_A = E_B
therefore
\frac{1}{2}mv_A^2 =  \frac{1}{2} mv_B^2 +  \frac{1}{2} mgh
and so
v_B^2 = v_A^2 - gh (1)

We know vA=30 m/s, however, we don't know the height h at the starting point. But we can calculate it by applying again the conservation of energy. At its starting point (let's label it point C), the roller coaster has only potential energy, because it starts from rest:
E_C = U_C = mgh
<span>The total energy must be equal to the total energy at ground level (point A), so
</span>E_A = E_C
\frac{1}{2}mv_A^2 = mgh
<span>from which we find
</span>h= \frac{v_A^2}{2g}= \frac{(30 m/s)^2}{2 \cdot 9.81 m/s^2} =45.9 m
<span>
And now we can substitute h into (1), to find the velocity of the roller coaster in point B:
</span>v_B =  \sqrt{v_A^2 - gh} = \sqrt{(30 m/s)^2-(9.81 m/s^2)(45.9m)} =21.2 m/s<span>
</span>
8 0
3 years ago
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