Solve the solution of this inequality 9−4d≥−3
2 answers:
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Answer: minimum = 0.5
maximum = 9.0
first quartile = 3
median = 5.5
third quartile = 7.5
Step-by-step explanation:
The histogram is shown below and used to obtain the various information
Time (hour) (X) No of People (F) FX
0.5 19 9.5 -- minimum = 0.5
1 20 20
1.5 21 31.5
2 22 44
2.5 23 57.5
3 24 72 ----first quartile = 3
3.5 26 91
4 27 108
4.5 28 126
5 29 145
5.5 30 165 --median/ inter quartile =5.5
6 31 186
6.5 32 208
7 33 231
7.5 34 255-- third quartile = 7.5
8 35 280
8.5 36 306
9 37 333 --- maximum = 9
T=85.5 T = 507 T= 2666.82 T = TOTAL
mean = sumFX/sumF = 2666.82/507 = 5.26
Median = middle number = inter quartile =5.5 (507/2 = 253.5 = 254 and add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29 =269
and 254 close to 269 that is the frequency is within the range and corresponds to 5.5
first quartile = 1/4 *507 = 126.75 = 127 ( add the frequency from top= 19+20+21+ 22+ 23+ 24= 129 and 127 is close to 129)
third quartile = 3/4 * 507 = 380.25 ( add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29+ 30+ 31+32+ 33+ 34 = 399 and 380 is close to 399 so the third quartile is 7.5
minimum is the one with lowest frequency = 0.5 at 19
maximum or mode is the one with highest frequency = 9 at 37
So, your answer to this problem is x > 6 and x < -2.