B.<span>Adding 15 to both sides of the equation.
A. Adding 8x to both sides wouldn't cancel anything out.
B. Adding 15 to both sides will cancel out 15 making it easier to solve for x.
C.Adding 3 to both sides will not cancel anything out.
D. Adding 2x to both sides won't cancel anything out. </span>
Answer:
The total number of unbroken / working slots
Step-by-step explanation:
Given that Devin's DVD case has 3 rows of slots, but 5 slots are broken
Also given that the number of slots in a row is x
1 row has x slots
3 rows has y slots
on cross multiplication we get y = 3x
ie there are a total of 3x slots in the 3 rows
Given that out of these 3x slots 5 . of the slots are broken
Therefore the total number of working slots = total number of slots - number of slots which are broken
total number of working slots are = 3x - 5
Therefore the given expression is the number of working / good slots
Answer: It is D
Step-by-step explanation:
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140
has a pvalue of 0.9772
X = 125
has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
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