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Gnoma [55]
2 years ago
5

A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not

selecting a red marble?
Mathematics
1 answer:
KonstantinChe [14]2 years ago
6 0

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

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31<9 and --3X = 4X = 15X = 12X = 11x = 18
JulsSmile [24]

Given:

\frac{3x}{4}

Find: values belong to the solution

Explanation:

\begin{gathered} \frac{3x}{4}

and

\begin{gathered} -\frac{x}{6}\ge-3 \\ -x\ge-18 \\ x\leq18 \end{gathered}

so those values are solution which is x<12

i.e; x=4 and x=11

5 0
1 year ago
A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?
LenKa [72]
We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.
3 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
Is the point (−7,1) a solution to the inequality
andrew-mc [135]
Question 1 true not false
8 0
3 years ago
HELP ASAP PLEASE!!!!!!!!!!!!!
zimovet [89]
X = 3/2
Y = -3

-6x-5(3-4x)=6
Y=3-4(3/2)
4 0
2 years ago
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