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padilas [110]
2 years ago
12

In a rigid motion, which of the following is/are preserved?

Mathematics
1 answer:
Arlecino [84]2 years ago
6 0

Answer:

2. Side lengths and angle measures

I guess

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Given a graph for the transformation of f(x) in the format g(x) = f(x) + k, determine the k value.
dimaraw [331]

Answer:

4

Step-by-step explanation:

g(x) is the graph of f(x) shifted up 4 units.

5 0
1 year ago
Solve ΔABC with ABC=51°, c=8 and a=11. Draw a diagram.
Rashid [163]

To solve a triangle means to obtain al the missing parts of the triangle.

<h3>How do you solve a triangle?</h3>

To solve a triangle means to obtain al the missing parts of the triangle. Now we have the following information;

<ABC = 51°

c = 8

a = 11

Then;

b^2 = a^2 + c^2 - 2acCos B

b^2 = (11)^2 + (8)^2 - [2 * 11 * 8 * cos 51]

b^2 = 121 + 64 - 55.38

b = 11.39

Now;

a/sinA = b/sinB

asinB = bsinA

sinA = asinB/b

sinA = 11 * sin 51/11.39

A = 48.6 or 49°

C = 180 - (49 + 51)

C = 80°

Learn more about triangles:brainly.com/question/2773823

#SPJ1

7 0
2 years ago
un frasco de jugo tiene una capacidad de 3/8 de litro ¿cuantos frascos se pueden llenar con cuatro litros y medio de jugo?
tangare [24]
Tenemos que

la capacidad del frasco es igual a 3/8 de litro
cuatro litros y medio es igual a decir 4 1/2 litros----> (4*2+1)/2----> 9/2 litros

realizamos una regla de tres
 si un frasco tiene capacidad para--------------> 3/8 litros
 X frascos-----------------------------------------> para 9/2 litros
X=(9/2)/(3/8)--------> 72/6-----> 12 frascos

la respuesta es
12 frascos
6 0
3 years ago
Can someone help with 11-15
lozanna [386]

Answer: -4


Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
2−2s=4/3 s+13 how do you do this
soldi70 [24.7K]

Answer: s = -3.3

<u>Step-by-step explanation:</u>

2-2s=\dfrac{4}{3}s+13\\\\\\\underline{\text{Multiply everything by 3 to clear the denominator:}}\\(3)2-(3)2s=(3)\dfrac{4}{3}s+(3)13\\\\.\qquad 6-6s=4s+39\\\\\\\underline{\text{Add 6s to both sides:}}\\.\qquad 6-6s+6s=4s+6s+39\\\\.\qquad \qquad \qquad 6=10s+39\\\\\\\underline{\text{Subtract 39 from both sides:}}\\.\qquad \qquad 6-39=10s+39-39\\\\.\qquad \quad \quad -33=10s\\\\\\\underline{\text{Divide both sides by 10:}}\\.\qquad \quad \quad \dfrac{-33}{10}=\dfrac{10s}{10}

                -3.3 = s

3 0
3 years ago
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