Answer:
6 seconds
Step-by-step explanation:
h(x)=-(x-2)^2+16
We want h(x) to be 0 ( that is when the ball hits the ground)
0 = -(x-2)^2+16
Subtract 16 from each side
-16 = -(x-2)^2+16-16
-16 = -(x-2)^2
Divide by -1
16 = (x-2)^2
Take the square root of each side
sqrt(16) = sqrt((x-2)^2)
±4 = x-2
Add 2 to each side
2±4 = x-2+2
2±4 =x
2+4 = x 2-4 = x
6 =x -2 =x
Time cannot be negative so x=6
Answer:
x = -5
Step-by-step explanation:
If g(x)= 3x - 12, and g(x)= -27 then -27 = 3x -12
Solve for x
-27 = 3x -12, add 12 to both sides
-27+12 = 3x, add -27+12
-15 = 3x, divide both sides by 3
-5 = x
Funciton form is f(x)=something
basicallly know that f(x) is the output or y
just solve for y
-3x-6y=0
add 3x to both sides
-6y=3x
divide both sides by -6
y=-1/2x
f(x)=(-1/2)x
Assuming you meant inches^3, V=4/3pir^3, substituting gives 28526=4/3pir^3 which simplifies to (3)(28526)/(4pi) which is equal to 6810 taking the cube root gives us the radius, 18.95
Answer:
1) 28m West 2)70km below sea level