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3 years ago

What is the length of side a? Round to the nearest tenth of an inch.

Mathematics

2 answers:

AlladinOne [14]3 years ago

7 0

Answer:

14.4 in.

Step-by-step explanation:

Given:

Base of a right triangle = 7 in

Height of a right triangle = a

Hypotenuse = 16 in

To find:

The length of side a.

Solution:

Using Pythagoras theorem:

In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.

Subtract 49 from both sides.

Taking square root on both sides, we get

a = 14.4

The length of side a is 14.4 in.

levacccp [35]3 years ago

5 0

Use Pythagorean theorem
a^2 + b^2 = c^2
You know b = 7, c = 16
Plug in the values
a^2 + 7^2 = 16^2
a^2 + 49 = 256
a^2 = 207
a = 14.38749
Round to nearest tenth
Solution: a = 14.4 in.

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shepuryov [24]

X=12 do you need an explanation?

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hram777 [196]

Answer:

B: 22.5 degrees

Step-by-step explanation:

The interior angles of a pentagon add up to 540 degrees

(if you dont believe me you can turn a pentagon into three triangles, 3x180 = 540)

So you have four same angles say measure "x" degrees, and one final one that measures "5x" degrees, so 9x = 540, and x = 60

Unless I read the problem wrong, 60 degrees is the answer which is not an option :P

Edit: Yea I read it wrong, the final angle is 5 times the other four angles COMBINED, so that angle measures "20x" degrees.

The total would be 24x = 540, and so x = 22.5

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Elis [28]

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Find the volume of a cylinder if it has a diameter of 8 and a height of 12. Leave your answer in terms of 70.

rewona [7]

If we need to choose the closest answer from the above given ones it is 6471.

SOLUTION:
Diameter(d)= 8
Radius(r)= d/2=8/2 =4,,
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So,
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3 years ago

Evaluate (6 + 2i) / (3 –i ). 5/4 + 6/4i 8/5 + 6/5i 20/8 + 12/8i 16/9 + 12/9i

Yuki888 [10]

We are given with a complex no. and need to simplify it , so let's start !!!

Let's assume that :

${:\implies \quad z=\sf \dfrac{6+2\iota}{3-\iota}}$

Now , Rationalizing the denominator or in other words multiplying and dividing ${z}$ by the conjugate of the denominator

${:\implies \quad z=\sf \dfrac{6+2\iota}{3-\iota}\times \dfrac{3+\iota}{3+\iota}}$

${:\implies \quad z=\sf \dfrac{(6+2\iota)(3+\iota)}{(3-\iota)(3+\iota)}}$

${:\implies \quad z=\sf \dfrac{6(3+\iota)+2\iota (3+\iota)}{(3)^{2}-(\iota)^{2}}\quad \qquad \{\because (a-b)(a+b)=a^{2}-b^{2}\}}$

${:\implies \quad z=\sf \dfrac{18+6\iota +6\iota +2(\iota)^{2}}{9-(-1)}\quad \qquad \{\because (\iota)^{2}=-1\}}$

${:\implies \quad z=\sf \dfrac{18+12\iota -2}{10}}$

${:\implies \quad z=\sf \dfrac{16+12\iota}{10}}$

${:\implies \quad z=\sf \dfrac{16}{10}+\dfrac{12\iota}{10}}$

${:\implies \quad {\bf \therefore}\quad \underline{\underline{z=\bf \dfrac{8}{5}+\dfrac{6}{5}\iota}}}$

Hence , Option B) (8/5) + (6/5)i is correct :D

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2 years ago