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kifflom [539]
3 years ago
5

How many grams are in 5.87 x 10^21 molecules of sulfur?

Chemistry
1 answer:
Stels [109]3 years ago
7 0

Answer:

0.312g

Explanation:

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of sulphur also contains 6.02x10^23 molecules

1mole of sulphur = 32g

If 1 mole(i.e 32g) of sulphur contains 6.02x10^23 molecules

Then, Xg of sulphur will contain 5.87x10^21 molecules i.e

Xg of sulphur = (32x5.87x10^21)/6.02x10^23 = 0.312g

just saying this is not my work, thank Eduard22sly

he answered it on a different page

so give him credit

here is the link

brainly.com/question/14966520

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