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3 years ago

We refer to astronauts in space as weightless, but not without mass. Why?

1 answer:

5 0

Weight is the force exerted by the gravity on that object, therefore when an astronaut is in space with no gravity he is weightless. Mass is the actual amount of matter contained in a body, this won’t change if the gravity changes.

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Will a helicopter work in a vacuum

Viefleur [7K]

No, there’s not any pressure

5 0

3 years ago

What is the wavelength, in nm, of the light photon emitted by a hydrogen atom when an electron goes from n

xxMikexx [17]

Answer:

Hence, the wavelength of the photon associated is 1282 nm.

Explanation:

8 0

3 years ago

How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?

jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

P= 7.5 atm
V= 2.3 L
n= ?

R= 0.082 $\frac{atm*L}{mol*K}$

T= 24 °C= 297 °K (being 0°C=273°K)

Replacing:

$7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K$

Solving:

$n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}$

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

$mass=\frac{0.708 moles*32 grams}{1mole}$

mass= 22.656 grams

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

8 0

3 years ago

Read 2 more answers

A reaction is spontaneous if delta G is 1)positive 2)negative 3)zero

miskamm [114]

delta g must be negative in order for the reaction to be spontaneous bb ♡

4 0

3 years ago

Read 2 more answers

Prepare 15 mg/dl working standard solution from a stock solution of 20 mg/dl. State the volume of diluent and dilution.

Anastasy [175]

Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.

Recalling the principle:

initial volume x initial molarity = final volume x final molarity

Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:

Applying the dilution principle:

10 x 20 = final volume x 15

final volume = 200/15

= 13.33 mL

This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.

More on dilution principle can be found here: brainly.com/question/11493179

4 0

3 years ago