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DerKrebs [107]
3 years ago
9

We refer to astronauts in space as weightless, but not without mass. Why?

Chemistry
1 answer:
fredd [130]3 years ago
5 0
Weight is the force exerted by the gravity on that object, therefore when an astronaut is in space with no gravity he is weightless. Mass is the actual amount of matter contained in a body, this won’t change if the gravity changes.
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I literally forgot! <br>What is chemistry?​
Art [367]

Answer:

Chemistry, the science that deals with the properties, composition, and structure of substances (defined as elements and compounds), the transformations they undergo, and the energy that is released or absorbed during these processes

5 0
3 years ago
Read 2 more answers
When optically active (S)-2-methylcyclopentanone is treated with aqueous base, the compound loses its optical activity. Explain
Sunny_sXe [5.5K]

Answer:

See explanation below

Explanation:

In this case, we need to see which is the structure of this compound. Now, racemization occurs basically because we are in an aqueous basic medium, and the ketone can reacts again with water in the medium to form the starting reagent.

First, the base will take out the Alpha hydrogen from the ketone, then, the negative charge goes down and opens up the carbonile group, forming a double bond in there. Later, with the water of the medium, it reacts and substract a proton, and then, with keto enolic equilibrium, forms again the ketone, but this ketone is different from the start, it will be the  R isomer which is not optically active.

See picture below for mechanism

3 0
3 years ago
A sample of fluorine gas exerts a pressure of 900 mmHg. When the pressure is changed to 1140 mmHg, the volume is 250 mL. What wa
UNO [17]
Let's use Boyle's Law here. P1*V1 = P2*V2
Given: (assuming that there are decimals at the end for Sig Figs)
P1 = 900.mmHg
P2 = 1140.mmHg
V1 = ???
V2 = 250.mL

900.mmHg* ??? = 1140.mmHg * 250.mL
??? = 1.27*250.mL
??? = 318.mL

Therefore, the original volume is 318mL.
8 0
3 years ago
Chlorine forms a number of oxides with the following oxidation numbers: 1, 3, 4, 6, and 7. These compounds are stable and neutra
SashulF [63]

Answer:

Cl_2O, Cl_2O_3, ClO_2, ClO_3, Cl_2O_7

Explanation:

Empirical formula of the compound is the simplest ratio of elements present in the compound.

Empirical formula of compounds of chlorine with oxygen is as follows:

Compounds in which oxidation state of Cl is +1

Cl_2O

Compounds in which oxidation state of Cl is +3

Cl_2O_3

Compounds in which oxidation state of Cl is +4

ClO_2

Compounds in which oxidation state of Cl is +6

ClO_3

Compounds in which oxidation state of Cl is +7

Cl_2O_7

8 0
3 years ago
The Ksp of silver bromide at 25°C (298 K) is 5.0 x 10-13. Write the solubility expression hydrogen oxygen for this compound and
Rufina [12.5K]
AgBr(s) <—> Ag+(aq) + Br-(aq)

Ksp = [Ag+][Br-]
5 0
2 years ago
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