The height of the building is 3.27 m
Since the question described free-fall under gravity, we will be using the equation for fall under gravity.
Using v² = u² - 2gh where u = initial velocity of toy = 0 m/s (since it is falls from rest), v = final velocity of toy as it hits the ground = 8 m/s, g = acceleration due to gravity = 9.8 m/s² and h = distance the ball falls = height of building
So, making h subject of the formula, we have
h = -(v² - u²)/2g
Substituting the values of the variables into the equation, we have
h = -(v² - u²)/2g
h = -[(8 m/s)² - (0 m/s)²)/(2 × 9.8 m/s²)
h = -(64 m²/s² - 0 m²/s²)/(2 × 9.8 m/s²)
h = -64 m²/s²/19.6 m/s²
h = -3.265 m
h ≅ -3.27 m
The value is negative since we take the top of the building as 0 m and downward direction as negative.
So, the height of the building is 3.27 m
Learn more about free fall here:
brainly.com/question/23180622
Answer:
C. A residual is the difference between the observed y-value of a data point and the predicted y-value on a regression line for the x-coordinate of the data point. A residual is positive when the point is above the line, negative when it is below the line, and zero when the observed y-value equals the predicted y-value.
Step-by-step explanation:
The residuals are obtained when there is some difference between the observed values and the fitted values of the data. Suppose we want to make a curve or hyperbola but the observed data does not actually give the curve required or there is some difference between the observed values and fitted values. The square of the sum of these differences is called residual.
The residual is positive when the point is above the line, negative when it is below the line, and zero when the observed y-value equals the predicted y-value.
Residual is obtained by subtracting the predicted value from observed value.This difference called the <u>residual</u> is
- positive when the observed value > predicted value
<em>For a positive value the point lies above the (fitted) line.</em>
- negative when the observed value < predicted value
<em>For a negative value the point lies below the (fitted) line.</em>
- zero when the observed value = predicted value
<em>For a zero value the point lies on the (fitted) line.</em>
Step-by-step explanation:
Answer:
I think it's B.)
Step-by-step explanation:
HIAB
1)H, 2)I, 3)A, 4)B.
When there is only points and no lines, to find domain, you give the x values only, and to find the range you give the y values only.
When there is a line, for domain you go from left to right, and for range you go from bottom to top. The arrow indicates that the line is continuous, and so the second values for domain and range are infinity because we do not know the value.
The value of f[ -4 ] and g°f[-2] are 
and 13 respectively.
<h3>What is the value of f[-4] and g°f[-2]?</h3>
Given the function;
- f[ -4 ] = ?
- g°f[ -2 ] = ?
For f[ -4 ], we substitute -4 for every variable x in the function.
For g°f[-2]
g°f[-2] is expressed as g(f(-2))
![g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13](https://tex.z-dn.net/?f=g%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%2B%205%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%2B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8x%2B3%7D%7Bx%2B1%7D%5C%5C%5C%5CWe%5C%20substitute%20%5C%20in%20%5C%20%5B-2%5D%20%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8%28-2%29%2B3%7D%7B%28-2%29%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-16%2B3%7D%7B-2%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-13%7D%7B-1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%2013)
Therefore, the value of f[ -4 ] and g°f[-2] are and 13 respectively.
Learn more about composite functions here: brainly.com/question/20379727
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