We know that ratios can be shown with both fractions and colons.
20:705
or

It also looks like we can simplify this by dividing by 5.
20/5 = 4
705/5 = 141.
This means that for every 4 teachers, there are 141 students.
The ratio for teachers to students is:
4 : 141
Answer: 9/25
Full equation: P(black) x P(black) = 12/20 x 12/20 = 3/5 x 3/5 = 9/25
Hope this helps answer B?
Answer:
See below
Step-by-step explanation:
Step 1.
P = $400
r = 0.04
t = 10 years
n = 12 ( as there are 12 months in a year).
Step 2.
A(10) = 400(1 + 0.04/12)^12^10
= 400 * 1.00333333^120
= $596.33 to the nearest hundredth (answer).
Answer:
x = 14
y = 14
z= 14
Step-by-step explanation:
Notice that the top triangle is a 45-45-90 triangle and the triangle below is a 30-60-90 triangle.
Using the fact that the top triangle is a 45-45-90 triangle and also an isosceles triangle, we can see that <em>x</em> will be the same as its respective leg, 14
Now, we must find a side length of the bottom triangle. We can use the Pythagorean Theorem to find the third side of the top triangle, which is also a side of the bottom triangle. We can find that the third side must be 28. We can now use this to find the other sides of the bottom triangle.
Since <em>y</em> is opposite to the 30 degree angle, it is half of the hypotenuse. The hypotenuse which we found earlier is 28, therefore, <em>y</em> is 14. <em>z </em>is then 14
using either Pythagorean Theorem or special right triangle properties for 30-60-90.
Given:
The given statement are:
a. Eight less than the product of seven and x.
b. The sum of six and the product of three and d.
To find:
The expression for the given statements.
Solution:
a.
Product of 7 and x is 7×x = 7x.
Eight less than the product of seven and x is 7x - 8.
Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.
b.
Product of 3 and d is 3×d = 3d.
The sum of six and the product of three and d is 6+3d.
Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.