The endpoints of the directed line segment AB are A(−2, −3) and B(10, 6) . Find the coordinates of point P along AB so that the
ratio of AP to PB is 2 to 1.
1 answer:
Answer:
(2, 0)
Step-by-step explanation:
Using the midpoint theorem;
M(X, Y) = {ax1+bx2/a+b, ay1+by2/a+b}
Given the coordinates A(−2, −3) and B(10, 6) divided within the ratio 2 to 1;
X = ax1+bx2/a+b
X = 2(-2)+1(10)/2+1
X = -4+10/3
X = 6/3
X = 2
Similarly;
Y = ay1+by2/a+b
Y = 2(-3)+1(6)/2+1
Y = -6+6/3
Y = 0/3
Y = 0
Hence the required coordinate P is at (2, 0)
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