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Gala2k [10]
3 years ago
14

The endpoints of the directed line segment AB are A(−2, −3) and B(10, 6) . Find the coordinates of point P along AB so that the

ratio of AP to PB is 2 to 1.
Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

(2, 0)

Step-by-step explanation:

Using the midpoint theorem;

M(X, Y) = {ax1+bx2/a+b, ay1+by2/a+b}

Given the coordinates A(−2, −3) and B(10, 6) divided within the ratio 2 to 1;

X = ax1+bx2/a+b

X = 2(-2)+1(10)/2+1

X = -4+10/3

X = 6/3

X = 2

Similarly;

Y = ay1+by2/a+b

Y = 2(-3)+1(6)/2+1

Y = -6+6/3

Y = 0/3

Y = 0

Hence the required coordinate P is at (2, 0)

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Answer:

FG = 47

Step-by-step explanation:

The opposite sides of a parallelogram are parallel and congruent, thus

EH = FG, that is

5z - 18 = 3z + 8 ( subtract 3z from both sides )

2z - 18 = 8 ( add 18 to both sides )

2z = 26 ( divide both sides by 2 )

z = 13

Hence

FG = 3z + 8 = (3 × 13) + 8 = 39 + 8 = 47

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3 years ago
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Step-by-step explanation:

8 0
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Read 2 more answers
Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

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  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

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3 years ago
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Andrews [41]

Answer:

B (r= 1/6s)

Step-by-step explanation:

If you just work out each option, you'll see that "s" multiplied by 1/6 gets r.

5 0
3 years ago
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