Et the numerator be x, so the denominator is x + 4. So we have:
<span>x/(x + 4) = 9/15 (cross multiply) </span>
<span>15x = 9(x + 4) </span>
<span>15x = 9x + 36 </span>
<span>15x </span>- 9x<span> = 9x - </span>9x<span> + 36 </span>
<span>6x = 36 </span>
6x/6<span> = 36</span>/6
x = 6
x + 4<span> = 6 + 4 = </span>10
<span>Sine the numerator is 6 and the denominator is 10, then the fraction is 6/10, which in the simplest form is equal to 3/5. </span>
<span>Since 9/15 in the simplest form is also equal to 3/5, then 6/10 is equivalent to 9/15. </span>
<span>Thus, 6/10 is the required fraction. hope i helped</span>
So this is a two step process, first you must find the area of the rectangle, then find the area of the semicircle.
So to find the area of a rectangle, you use: Length*Height=Area
In this case that would be: 7*2=14cm
Next you find the area of the semicircle, to do this you first find the area of the circle (Pi*r^2) then divide it by 2.
The diameter of the circle is 4 because: 7-2-1=4cm
Next divide that by 2 so that you get the radius: 4/2=2cm
Not you can plug that into the equation to get the area of the circle: Pi*2^2<span>≈13cm^2
Next divide it by 2 so that you get the area of the semicircle:13/2</span><span><span>≈</span>6cm^2
At this point you can add the area of the semicircle to the area of the rectangle: 14+6=20cm^2
So your final answer is 20cm^2!
</span>
Answer:
310
Step-by-step explanation:
1.75×39=68.25
241.75+68.25=310
![\sqrt[3]{a} = {a}^{m} \\ = > { a}^{ \frac{1}{3} } = {a}^{m} \\ = > m = \frac{1}{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Ba%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20%20%7B%20a%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20m%20%3D%20%20%5Cfrac%7B1%7D%7B3%7D%20)
<u>Answer</u><u>:</u>
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Hope you could understand.
If you have any query, feel free to ask.
Step-by-step explanation:
