Answer:
0.005 `; 0.00499 ;
No, because np < 10 ;
2000
Step-by-step explanation:
Given that:
Number of samples , n = 100
Proportion, p = x / n
p = 1 / 200
= 0.005
p = μ
Standard deviation of sample proportion :
σp = sqrt((p(1 - p)) / n)
σp = sqrt((0.005(1 - 0.005)) / 200)
σp = sqrt((0.005(0.995)) / 200)
σp = sqrt(0.004975 / 200)
σp = sqrt(0.000024875)
σp = 0.0049874
σp = 0.00499
np = 100 * 0.005 = 0.5
n(1 - p) = 100(1-0.05) = 95
Smallest value of n for which sampling distribution is approximately normal
np ≥ 10
0.005n ≥ 10
To obtain the smallest value of n,
0.005n = 10
n = 10 / 0.005
n = 2000
g- acceleration due to gravity=9.8ms^-2
acceleration of performer= 1.5g = 1.5 x 9.8ms^-2 = 14.7ms^-2
Answer:
≤ 14
Step-by-step explanation:
2 * x - 5 ≤ 18
divide 2 from both sides.
x - 5 ≤ 9
the answer is less than or equal to 14
See, please, suggested decision, if it is possible check it.