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3 years ago

11

3y^2+12y=0 plz helppp!! Solve for y

2 answers:

Butoxors [25]3 years ago

6 0

Answer:

y = 0, -4

Step-by-step explanation:

1) Factor out the common term 3y.

$3y(y + 4) = 0$

2) Solve for y.

<em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>-4</u></em>

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>-4</u></em><em><u>.</u></em>

Kazeer [188]3 years ago

5 0

Answer:

y=4

Step-by-step explanation:

3y2+12y=0

Step 1: Factor left side of equation.

3y(y+4)=0

Step 2: Set factors equal to 0.

y+4=0

y=−4

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