Answer:
y² - (K- 2)y + 2k +1 = 0
equal roots means D=0
D= b^2 - 4ac
a=1, b= (k-2), c= 2k+1
so,
(k-2)^2 - 4(1)(2k+1) = 0
=> k^2 +4 - 8k -4 = 0
=> k^2 -8k = 0
=> k^2 = 8k
=> k= 8k/k
=> k = 8
Therefore the answer is k= 8
Hope it helps........
Answer:y = x 2 − 12 x The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Interval Notation: ( − ∞ , ∞ ) Set-Builder Notation: { x | x ∈ R } The range is the set of all valid y values. Use the graph to find the range. Interval Notation: [ − 36 , ∞ ) Set-Builder Notation: { y | y ≥ − 36 } Determine the domain and range. Domain: ( − ∞ , ∞ ) , { x | x ∈ R } Range: [ − 36 , ∞ ) , { y | y ≥ − 36 }
Step-by-step explanation:
Answer: what am I suppose to do with that?
Step-by-step explanation:
