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3 years ago

Solve each inequality 2v>10

2 answers:

34kurt3 years ago

4 0

Hey there

Solution

1) Divide each side by 2
v > $\frac{10}{2}$

2) Simplify $\frac{10}{2}$ to 5
v>5

Answer -- v>5

balandron [24]3 years ago

4 0

2v>10
Divide each side by 2
v>5
I hope this helps;)

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If a ladder is to be placed 3 feet from the side of a house. If top of the ladder rests exactly on the edge of the house when it

likoan [24]

Answer:

7 feet long

Step-by-step explanation:

This set up will give a right angle triangle where;

Length of the ladder is the hypotenuse = x

The distance of the ladder to the house is the adjacent = 3 feet

Angle of elevation theta = 72 degrees

Using the CAH in trigonometry identity;

cos theta = adjacent/hypotenuse

cos 72 = 3/hyp

hyp = 3/cos72

hyp = 3/0.4258

hyp = 7.05 feet

Hence the ladder is approximately 7 feet long

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3 years ago

What is the value of m in 3(2m-9+6m)=3m+29-7m i got 1/10 but the choices are -3, 2, 5, and 120

kirill [66]

Hello,

3(2m-9+6m)=3m+29-7m
==>3(8m-9)=-4m+29
==>24m+4m=29+27
==>28m=56
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Answer B

5 0

3 years ago

Read 2 more answers

Graph the solution set for the inequality z-4≤3

OleMash [197]

Answer:

see below

Step-by-step explanation:

Add 4 to find the solution:

z ≤ 7

The value 7 is included in the solution set, so there will be a solid dot at that point. Numbers less than 7 are also included in the solution set, so the number line will be shaded to the left of that solid dot.

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3 years ago

The image below shows the download speed of three different companies. Use the information to answer the questions.

inessss [21]

Answer:

1) The download speed for AT&T is 1,800

2) The download speed for Bidmore is 1,500

3) The download speed for Comcast is 1,680

4) AT&T has the best download speed out of the three.

5) They will go through the origin and be a proportional line.

Step-by-step explanation:

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3 years ago

What is the simplified expression for,

Nostrana [21]

Here are a few rules you need to know for this equation:

Multiplying exponents of the same base: $x^m\times x^n=x^{m+n}$
Dividing exponents of the same base: $\frac{x^m}{x^n}=x^{m-n}$
Turning a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m$