Answer: No the students work is not correct. Because you are using distribution. Which means that 3 has to multiply the y2 and 2 not just the y2! And after you distribute it you need to simplify!
Step-by-step explanation:
The slope should be one over two.
The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.
The solution
To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.
The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.
6/2 = 3
10/2 = 5
4/2 = 2
1/2(10C6) - (5C3) + (5C3)
0.5(210-10+10)
= 110
They want you to write the number in index form.
The number is 5N^2, where N = 3 x 5^2 x x^3
So:
5N^2 = 5 x (3 x 5^2 x x^3)^2
= 5 x (3^2 x 5^4 x x^6)
= 3^2 x 5^5 x x^6
or a bit neater looking: 3² ₓ 5⁵ ₓ x⁶
Answer:
Since we have a^7 on the Numerator and after simplification... No "a" was left in the expression. It simply means that all a's in the numerator was eliminated and 2a's were left in the denominator.
To eliminate a^7 and still have 2a's as a remainder in the denominator... 'n' must be equal to 9
So
n=9
