Answer:
1.533 moles Au
Explanation:
To find the moles from atoms, you just use Avogadro's number (6.02214076×10^23 mol^-1) and divide by it. Hope this helped!
The mass of carbon dioxide produced from the complete combustion of 4.80 x10^-3 g of methane is 0.0132 grams
calculation
write the equation for combustion of methane (CH4)
CH4 + 2O2 → CO2 + 2H2O
find the moles of CH4 used = mass/molar mass
molar mass of CH4 = 12 +(1 x4) = 16 g/mol
moles =( 4.80 x10^-3 g) / 16 g/mol = 3 × 10^-4 moles
by use of mole ratio between Ch4 to CO2 which is 1:1 the moles of CO2 is also = 3 x10^-4 moles
mass of CO2 is therefore = moles x molar mass of Co2
The molar mass of Co2 = 12 +(16 ×2) = 44 g/mol
mass is therefore = (3 ×10^-4 moles) ×44 g/mol = 0.0132 grams
Answer: B.
Explanation:
To find the conjugate base, you add a hydrogen ion and add 1 to the overall charge.
The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
<h3>How to calculate [H3O+]?</h3>
The hydrogen ion concentration of a solution can be calculated as follows:
pOH = - log [OH-]
pOH = - log [6.3 × 10-⁷M]
pOH = - [-6.2]
pOH = 6.2
Since pOH + pH = 14
pH = 14 - 6.2
pH = 7.8
pH = - log [H3O+]
7.8 = - log [H3O+]
[H3O+] = 10-⁷:⁸
[H3O+] = 1.5 × 10-⁸M
Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
Learn more about hydrogen ion concentration at: brainly.com/question/15082545