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Dafna11 [192]
3 years ago
9

Give the formula of a reagent which will form a

Chemistry
1 answer:
Sloan [31]3 years ago
5 0

Answer:

The group reagent is H2S in the presence of NH4Cl .

Explanation:

Mn is fourth group radical in qualitative analysis ;

           the group reagent is H2S in the presence of NH4Cl .

then Mn precipitates as buff coloured sulphide , which is soluble in HCl .

    MnS + 2HCl --------->  MnCl2 + H2S

on heating the solution with NaOH with bromine water, manganesedioxide gets precipitated.

MnCl2 + 2NaOH --------> Mn(OH)2 + 2NaCl

Mn(OH)2 + O -------> MnO2 + H2O

  whereas NiS is insoluble in HCl. the nickel chloride gives a scarlet red precipitate with dimethy gly oxime.

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The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

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8 0
3 years ago
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To calculate the density of a sample of matter,you must divide it_____ by its______.
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A chemist prepares a solution of sodium carbonate by measuring out of sodium carbonate into a volumetric flask and filling the f
Vadim26 [7]

Answer:

The correct answer will be "9.45\times 10^{-5} \ mol/L".

Explanation:

We have:

Moles of solute (Na₂Co₃) = 18.9 \mu \ mol

                                           = 18.9\times 10^{-6}

                               1 \mu \ mol = 10^{-6} \ mol

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The volume of the solution will be:

⇒  0.200 \ L

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The formula to find the concentration will be:

⇒  Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}

On substituting the given values, we get

⇒                          =\frac{18.9\times 10^{-6}}{0.200}

⇒                          =9.45\times 10^{-5} \ mol/L

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