Question

A reaction was performed in which 0.55 g of 2-naphthol was reacted with a slight excess of 1-bromobutane to make 0.32 g of 2-butoxynaphthalene. Calculate the theoretical yield and percent yield for this reaction.

Answer 1

Answer:

Theoretical yield=0.764 g.

Percent yield 42%.

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture. In such a way, starting by the given mass of 2-naphtol, one computes the theoretical yielded grams of 2-butoxynaphthalene as shown below, considering their 1 to 1 molar relationship:

$m_{2-butoxynaphthalene}=0.55g2-naphtol*\frac{1mol2-naphtol}{144.17g2-naphtol}*\frac{1mol2-butoxynaphthalene}{1mol2-naphtol}*\frac{200.28g2-butoxynaphthalene}{1mol2-butoxynaphthalene}=0.764g2-butoxynaphthalene$

Moreover, the percent yield turns out:

$Y=\frac{0.32g}{0.764g}*100\% =42\%$

Best regards.