Answer:
302 m³
Step-by-step explanation:
The volume (V) of a cone is calculated using the formula
V = 
πr²h
where r is the radius and h the height
Consider the right triangle from the vertex of the cone to the midpoint of the base and the radius
with hypotenuse = 10 cm
h² + 6² = 10²
h² + 36 = 100 ( subtract 36 from both sides )
h² = 64 ( take the square root of both sides )
h = 
= 8
Hence
V = π × 6² × 8
= π × 36 × 8
= 
≈ 302 m³
Answer: 4cm x 4cm x 4cm = 64cm
Step-by-step explanation:
4x4 = 16x4 = 64
Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
</span>
Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
<span />
7(5)-12(5)-5=-45+15
-30 = -30
answer= B. x=5
<h2>Answer:</h2><h3>W = 5</h3><h3>Step-by-step explanation:</h3><h3>Simplify the brackets. </h3><h3>-2x^2 + wx - 4 - x^2 - 5x - 6 = -3x^2 - 10</h3><h3>Then simplify (-2x^2 + wx - 4 - x^2 - 5x - 6) to </h3><h3>( -3x^2 + wx - 10 - 5x)</h3><h3>This will give you 3x^2 + wx - 10 - 5x = -3x^2 - 10. </h3><h3>Now you need to cancel out -3x^2 on both sides. </h3><h3>wx - 10 - 5x = -10</h3><h3>Then cancel out -10 from both sides. </h3><h3>wx - 5x = 0</h3><h3>Now factor out the common term. (x) </h3><h3>w - 5 = 0.</h3><h3>giving you the answer w = 5. </h3><h3 /><h3 /><h3>welcome. *yeets*</h3>
