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olya-2409 [2.1K]
4 years ago
5

What fomula can be used to describe the sequence? -2/3,-4,-24,-144

Mathematics
1 answer:
Lunna [17]4 years ago
5 0

This is a geometric sequence with n th term formula

a_{n} = a_{1}(r)^{n-1}

where r is the common ratio and a_{1} the first term

here a_{1} = - \frac{2}{3} and

r = \frac{-144}{-24} = \frac{-24}{-4} = 6

a_{n} = - \frac{2}{3}(6)^{n-1}

or in terms of x

f(x) = - \frac{2}{3}(6)^{x-1}



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Then multiply variables. So x^(2+1) and it gives you x^3. Then y^(3+2) and it gives you y^5.
The final answer is -15x^3y^5
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\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\implies x^{\frac{2}{5}}\implies \sqrt[5]{x^2}
\\\\\\
and\implies (4ab)^{\frac{3}{5}}\implies \sqrt[5]{(4ab)^3}\implies \sqrt[5]{4^3a^3b^3}
\\\\
-----------------------------\\\\

now\\\\ 4\to 2^2\qquad and\qquad 4^3\to (2^2)^3\to 2^{2\cdot 3}\to 2^6\to 2^{5+1}\to 2^52^1\\\\
-----------------------------\\\\



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Step-by-step explanation:

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