Solvation describes the interaction of solvent with dissolved molecules.
Answer:
0.0187 M
Explanation:
Step 1: Write the balanced neutralization reaction
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
18.7 mL of 0.01500 M HCl react.
0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.
Step 4: Calculate the molarity of NaOH
2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.
[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M
Answer:
This question is incomplete
Explanation:
This question is incomplete but what you should know is that isopropanol (also referred to rubbing alcohol) has just one functional group. This functional group is called the hydroxyl group (-OH) and it's the reason the compound name ends with "ol". The hydroxyl group can be seen in the structure of the compound (Isopropanol) below
H OH H
| | |
H- C - C - C - H
| | |
H H H
If there is any functional group in isopropanol required for any form of interaction, that functional group will be the hydroxyl group because that's the only functional group isopropanol has.
NOTE: Functional group is an atom or group of atoms that determines the chemical properties of a compound.
The movement of these tectonic plates is likely caused by convection currents in the molten rock in Earth's mantle below the crust. Earthquakes and volcanoes are the short-term results of this tectonicmovement. The long-term result of plate tectonics is the movement of entire continents over millions of years
Answer:
Explanation:
A chemical formula is representation of a compound. Compounds are made up of two or more elements combining together.
The chemical formula of any compound is a representation which shows the elements therein and the mole relationship expressed as subscripts.
Elements in HCl - Hydrogen (H)
Chlorine (Cl)
Here 1 mole of hydrogen chloride molecule consists of 1 mole of chlorine atoms and 1 mole of hydrogen atoms.