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2 years ago

What is the atomic radius

Chemistry

1 answer:

dimaraw [331]2 years ago

5 0

Answer:

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

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50 POINTS

Trava [24]

My guess is b for the question

3 0

2 years ago

Read 2 more answers

The air inside a hot-air balloon is heated to 59.00 °C (Tinitial) and then cools to 39.00 °C (Tfinal). By what percentage does t

Mama L [17]

Answer:

6.1%

Explanation:

Assuming pressure inside balloon remains constant during the temperature change.

Therefore, as per Charles' law at constant pressure,

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

$T_2=39\°\ C=39+273=312\ K$

$T_1=59°\ C=273+59=332\ K$

$V_2=V_1\times \frac{T_2}{T_1} \\=V_1\times\frac{312}{332}\\=0.939V_1$

Percentage change in volume

$\%\ change\ in\ volume=\frac{V_1-0.939V_1}{V_1} \times 100\\=6.1\%$

Change in volume of the balloon is 6.1%

4 0

3 years ago

The chemical formula for lithium phosphide is li3p

Oxana [17]

Sodium phosphide is the inorganic compound with the formula Na3P.

4 0

3 years ago

Which of the tests would involve a chemical change in the mineral?

Shkiper50 [21]

hmmm water

Explanation:

Water can change if you put food coloring

in it

8 0

2 years ago

238 U 92 write the following decay sequence.

Vladimir [108]

Answer: The given decay sequence is $^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$ .

Explanation:

An alpha-particle is a helium atom. Hence, when an alpha decay occurs in $^{238}_{92}U$ then the reaction equation is as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He$

Now, in sequence the equation for beta decay is as follows.

$^{234}_{90}Th \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$

Hence, the sequence will be as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$

Thus, we can conclude that the given decay sequence is $^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He \rightarrow ^{234}_{91}Pa + ^{0}_{-1}\beta$ .

4 0

3 years ago