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Sphinxa [80]
4 years ago
13

Which electrons in an atom make chemical bonds? why?

Chemistry
1 answer:
nikdorinn [45]4 years ago
4 0
Valence (outermost) electrons. Chemical bonds are formed when an atom does not have a full outermost shell, i.e. there are 7 electrons and 1 more is needed, or there is only 1 electron, which can be transferred to another atom.
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How many milliliters of 2.5 M HCl are required<br> to exactly neutralize 1.5 L of 5.0 M NaOH?
Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

7 0
4 years ago
Both diamond and graphite (i.e. pencil lead) consist of carbon atoms. They are only different in their crystalline structures. O
prisoha [69]

Answer:

Moles of carbon atoms  = 3.33  ×  10^{-6} mol

No. of atoms of C in Diamond  = 2.007 ×   10^{28} atom

Atoms of graphite = 6.27 × 10^{23} Atoms

Explanation:

given data

Cost of 0.2g of diamond = $5000

Cost of 25 g of graphite = $ 2

solution

we know cost of 0.2g of diamond is $ 5000 so that for 1$

if buy 1$ = \frac{0.20}{5000}

1$ = 4.0 × 10^{-5} g Carbon

and Moles of carbon atoms  is express as

Moles of carbon atoms = Given mass of Carbon ÷ atomic mass of C      .........1

Moles of carbon atoms  = 4.0  ×  10^{-5}    g/ 2.0g

Moles of carbon atoms  = 3.33  ×  10^{-6} mol

and

No. of atoms of C in Diamond = No. of moles × Avogadro NO    ..............2

No. of atoms of C in Diamond  = 3.33 ×   10^{-6} mol × 6.022 ×   10^{28}

No. of atoms of C in Diamond  = 2.007 ×   10^{28} atom

Graphite

and wew have given Cost of 25 g of graphite is $2 so for but 1$ we get

for buy $1 = 25÷2  = 12.5 g Of graphite

Moles of graphite = 12.5÷12 = 1.04 mol

Atoms of graphite = 1.04 × 6.022 × 1023

Atoms of graphite = 6.27 × 10^{23} Atoms

6 0
3 years ago
What determines gravitational pull?
vlabodo [156]
Hello there!

From my calculations the answers are:

D. Mass

B. Gravity

B. Gravity

Hope This Helps You!
Good Luck :)

8 0
3 years ago
Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone​
bulgar [2K]

Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)

6 0
3 years ago
A canister of acetylene has a volume of 42 L. The temperature of the acetylene is 305 K and the pressure is 780 torr. Determine
stellarik [79]
First, we need to assume acetylene to adapt an ideal gas behavior. So, we can use the Ideal Gas Law:

PV = nRT

Given:

V = 42 L
T = 305 K
P = 780 torr = 1.026 atm 
R = gas constant, 0.0821 L atm/ mol K
n = amount of gas in the canister

1.026 atm * 42 L = n * 0.0821 L atm/mol K * 305 K

n = 1.72 moles of gas 


3 0
4 years ago
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