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likoan [24]
2 years ago
14

How do you determine the group and period of an element based on its electron configuration?

Chemistry
1 answer:
il63 [147K]2 years ago
4 0

Answer:

If you are given with the atomic number of an element you can find it's period number and group number. The period number is related to the number of electron occupied shells in the element and the period number is linked to its valence electrons.

Explanation:

hope it helps luv <3

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Not gonna lie.....I need help with this my guy.
ElenaW [278]
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5 0
3 years ago
How many mol are in 8.23 x 10^24 formula units of calcium carbonate
tensa zangetsu [6.8K]

Answer:

13.7 moles

Explanation:

Given data:

Number of moles calcium carbonate = ?

Formula units calcium carbonate= 8.23 × 10²⁴

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.23 × 10²⁴ formula units:

one mole = 6.022 × 10²³ formula units

8.23 × 10²⁴ formula units × 1 mole /6.022 × 10²³ formula units

13.7 moles

7 0
3 years ago
The information below describes a redox reaction.
Rashid [163]

Answer:

Al°(s)  + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)

Explanation:

Oxidation:                            Al°(s) =>   Al⁺³(aq) + 3e⁻

Reduction:           3Ag⁺(aq) + 3e⁻ => 3Ag°(s)

_________________________________________

Net Rxn:           Al°(s)  + 3Ag⁺(aq) => Al⁺³(aq) + 3Ag(s)

One mole of neutral aluminum atoms (Al°(s)) undergo oxidation delivering 3 moles  of electrons to 3 moles silver ions (3Ag⁺³(aq)) that are reduced to 3 moles of neutral silver atoms (3Ag°(s)) in basic standard state 25°C; 1atm.

7 0
3 years ago
What formula was used to find the answer
Setler79 [48]
Can you give more information?
6 0
2 years ago
An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi
arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

             r = \frac{mv}{qB}

where,   m = mass,      v = velocity

              q = charge,    B = magnetic field

Therefore, q will be calculated as follows.

         q = \frac{mv}{rB}

            = \frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}

            = \frac{34.98 \times 10^{-22}}{0.01092}

            = 3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}

            = +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0
2 years ago
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