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likoan [24]
2 years ago
14

How do you determine the group and period of an element based on its electron configuration?

Chemistry
1 answer:
il63 [147K]2 years ago
4 0

Answer:

If you are given with the atomic number of an element you can find it's period number and group number. The period number is related to the number of electron occupied shells in the element and the period number is linked to its valence electrons.

Explanation:

hope it helps luv <3

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Answer:

Convert the mass of each element to moles using the molar mass from the periodic table. then Divide each mole value by the smallest number of moles calculated. Round to the nearest whole number

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Does salt water or fresh water freeze faster
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Find the mass of each of these substances? 2.40 mol NaOH
damaskus [11]
Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

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Which experiment lead to the discovery that the tiny, dense nucleus contained most of
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The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Alexxx [7]

<u>Answer:</u> The vapor pressure of solution is 459.17 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For testosterone:</u>

Given mass of testosterone = 7.752 g

Molar mass of testosterone = 288.4 g/mol

Putting values in equation 1, we get:

\text{Moles of testosterone}=\frac{7.752g}{288.4g/mol}=0.027mol

  • <u>For diethyl ether:</u>

Given mass of diethyl ether = 208.0 g

Molar mass of diethyl ether = 74.12 g/mol

Putting values in equation 1, we get:

\text{Moles of diethyl ether}=\frac{208.0g}{74.12g/mol}=2.81mol

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{testosterone}}=\frac{n_{\text{testosterone}}}{n_{\text{testosterone}}+n_{\text{diethyl ether}}}

\chi_{\text{testosterone}}=\frac{0.027}{0.027+2.81}\\\\\chi_{\text{testosterone}}=0.0095

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,

p^o = vapor pressure of solvent (diethyl ether) = 463.57 mmHg

p^s = vapor pressure of the solution = ?

i = Van't Hoff factor = 1 (for non electrolytes)

\chi_{\text{solute}} = mole fraction of solute (testosterone) = 0.0095

Putting values in above equation, we get:

\frac{463.57-p^s}{463.57}=1\times 0.0095\\\\p^s=459.17mmHg

Hence, the vapor pressure of solution is 459.17 mmHg

7 0
3 years ago
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