Oxygen = 16
Iron = 55.8
16 x 27.6% = 4.4 /4 = 1.1
55.8 x 72.4% = 40.4 /4 = 10.1
1 oxygen and 10 iron, so Fe10 O
The number of neon moles that occupy a volume of 14.3 l at STP is calculated as follows
At STP 1 mole = 22.4 liters
what about 14.3 liters
by cross multiplication
= (1 mole x 14.3 l)/22.4 l =0.638 moles of neon
Answer:
660J/kg.°C
Explanation:
Using the fact that
∆E of metal + ∆E of water = 0
∆E of the metal = Q = m*c*(T2-T1)
Where
Q = heat lost or gained = ?
m = mass of metal in kg = 0.076kg
c = specific heat of the metal = ?
T1 = 96°C
T2=31°C
∆E of the water=Q= m*c*(T2-T1)
Where
Q = 0.120*4180*6.5 = 3260J
Therefore
3,260J + Q of the metal =0
3,260J + 0.076*C*(31.0–96.0)=0
3,260J - 4.94c = 0
3,260 = 4.94c
3,260/4.94 = c
660J/kg.°C = specific heat of the metal
hope this helps:)
You're right, it's a solid at room temperature :)
<span>This is a physical property. Physical properties involve changes of phase, or state of matter, of which melting is an example. Melting involves a change from a solid state to a liquid state. The internal energy of the solid increases, usually by applying heat, which increases the temperature to the melting point of the substance.</span>