Answer:
15g
Explanation:
Molar mass of acetic acid = 60g/mol
Molarity = mass ÷ molar mass
mass = 0.25 × 60
= 15g
∴ 15g of acetic acid weighed into 1L volumetric flask would give 0.25M of acetic acid.
<em>Alternatively, if the solution is being prepared from a stock solution of known concentration, (say 500mL of 0.5M solution), the formular C2V1 =C2V2 can be used to find the dilution volume.</em>
Hi!
Let me complete the question for you.
Trial Count Percent Error Trial 1 0,05
Trial 2 0,02
Trial 3 0,01
The most accurate value is the one From
Trial 3
Percent Error is a measure of the difference between the experimental value and a theoretical one. The equation for calculating the percent error is shown below:
Results are more accurate as the Percent Error is lower, so as Trial 3 has the lowest percentage error, the result of it would be the most accurate.
Have a nice day!
Answer:
Explanation:
Mallabone’s tests suggest there’s no risk the jacket liner will explode or heat up so much that it risks causing burns. The reaction also doesn’t produce acidic byproducts. And because calcium oxide doesn’t react with humidity (water vapor in the air), the liners can be stored for long periods and still work when needed.
Calcium oxide: A substance that gives off heat as it chemically reacts with water. Its chemical formula is CaO (which means each molecule is made up of one calcium atom and one oxygen atom).
Exothermic reaction: A chemical reaction that generates heat as it proceeds. (In Greek, “exo” means outside and “therm” means heat.)
Thought this might help ;)
See Figure 4 below.
1. Draw a 7-carbon chain and number the carbon atoms (<em>Figure 1</em>).
2. Insert a triple bond between atoms 5 and 6 (<em>Figure 2</em>).
3. Attach a phenyl group to atom 3 (<em>Figure 3</em>).
4. Attach a Br to atom 1 (Figure 4).
And you have your structure.
<em>Note</em>: The C≡C triple bond takes <em>priority</em> in the naming, so we must number the chain from the other end. The correct name is
<em>7-bromo-5-phenylhept-2-yne </em>(all one word).
The molarity of the lake water is 0.00001 M and the pH of lake water is 5.
The lake water is acidic.
Explanation:
Data given:
molarity of base solution Mbase = 0.1 M
volume of the base solution Vbase = 0.1 ml or 0.0001 litre
volume of lake water Vlake = 1000ml or 1 litre
molarity of the lake water, Mlake = ?
Using the formula for titration:
Mbase X Vbase = Mlake X
Mlake =
Putting the values in the equation:
Mlake =
Mlake = 0.00001 M
The pH of the lake water will be calculated by using the following formula:
pH = - []
pH = - [ 0.00001]
pH = 5