Through mass spectrometry, we can define 4 different isotopes of the BrCl molecule:
⁸¹Br³⁷Cl, ⁸¹Br³⁵Cl, ⁷⁹Br³⁷Cl, ⁷⁹Br³⁵Cl
Masses of the different individual isotopes:
³⁷Cl=36.966
³⁵Cl=34.968
⁸¹Br=80.916
⁷⁹Br=78.918
Masses of 4 different isotopes of the BrCl molecule:
⁸¹Br³⁷Cl=80.916+36.966=117.882
⁸¹Br³⁵Cl=80.916+34.968=115.884
⁷⁹Br³⁷Cl=78.918+36.966=115.884
⁷⁹Br³⁵Cl=78.918+34.968=113.886
Answer:
frequency = 8.22 x 10¹⁴ s⁻¹
Explanation:
An electron's positional potential energy while in a given principle quantum energy level is given by Eₙ = - A/n² and A = constant = 2.18 x 10⁻¹⁸j. So to remove an electron from the valence level of Boron (₅B), energy need be added to promote the electron from n = 2 to n = ∞. That is, ΔE(ionization) = E(n=∞) - E(n=2) = (-A/(∞)²) - (-A/(2)²) = [2.18 x 10⁻¹⁸j/4] joules = 5.45 x 10⁻¹⁹ joules.
The frequency (f) of the wave ionization energy can then be determined from the expression ΔE(izn) = h·f; h = Planck's Constant = 6.63 x 10⁻³⁴j·s. That is:
ΔE(izn) = h·f => f = ΔE(izn)/h = 5.45 x 10⁻¹⁹ j/6.63 x 10⁻³⁴ j·s = 8.22 x 10¹⁴ s⁻¹
Answer:
it would be an element because its an element
Explanation:
Answer: The answer is an ionic bond