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andrew-mc [135]
3 years ago
6

941 milliliters is the same as: cm3 and L

Chemistry
2 answers:
Nutka1998 [239]3 years ago
6 0

For this case, we must take into account the following conversion factors:

1 mL = 1 cm ^ 3

1000 mL = 1 L

Therefore, by applying the conversion factors we have:

For cubic centimeters:

(941mL) (1\frac{cm^3}{mL}) = 941cm ^ 3

For liters:

(941mL) (\frac{1}{1000}\frac{L}{mL}) = 0.941L

Answer:

941 milliliters is the same as:

941cm ^ 3

0.941L

Dimas [21]3 years ago
6 0
1 l = 1000 cm*3 = 1000ml

Therefore, 941 ml is equal 0.941 l and 0.941 cm*3
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A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
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Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

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3 years ago
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