Gas and radio waves I’m pretty sure is correct
Answer:
pH = 1.85
Explanation:
The reaction of H₂NNH₂ with HNO₃ is::
H₂NNH₂ + HNO₃ → H₂NNH₃⁺ + NO₃⁻
Moles of H₂NNH₂ and HNO₃ are:
H₂NNH₂: 0.0400L ₓ (0.200mol / L) = 8.00x10⁻³ moles of H₂NNH₂
HNO₃: 0.1000L ₓ (0.100mol / L) = 0.01 moles of HNO₃
As moles of HNO₃ > moles of H₂NNH₂, all H₂NNH₂ will react producing H₂NNH₃⁺, but you will have an excess of HNO₃ (Strong acid).
Moles of HNO₃ in excess are:
0.01 mol - 8.00x10⁻³ moles = 2.00x10⁻³ moles of HNO₃ = moles of H⁺
Total volume is 100.0mL + 40.0mL = 140.0mL = 0.1400L.
Thus, [H⁺] is:
[H⁺] = 2.00x10⁻³ moles / 0.1400L = 0.0143M
As pH = - log [H⁺]
<h3>pH = 1.85 </h3>
23.9 11.00 would be the wrong answer because I guessed
Under strongly acidic conditions aldoses become oxidised to dicarboxylic acids called aldaric acids
<h3>
What are aldaric acids?</h3>
The formula for aldaric acids is HOOC-(CHOH)n-COOH, and they are a kind of sugar acids in which the sugars' terminal hydroxyl and carbonyl groups have been substituted by terminal carboxylic acids.
Aldoses are often oxidised with nitric acid to produce aldaric acids. The open-chain (polyhydroxyaldehyde) form of the sugar interacts in this reaction.
Aldoses that have both the hydroxyl function of the terminal carbon and the aldehyde function of the first carbon completely oxidised to carboxylic acid functions are referred to as aldaric acids. (Aldonic acid is produced by oxidising just the aldehyde, whereas uronic acid is produced by oxidising only the terminal hydroxyl group.) Like unoxidized sugars, aldaric acids cannot produce cyclic hemiacetals, but they occasionally can form lactose.
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Answer:
D. Solutions are formed when the water’s polar molecules separate the polar molecules of an ionic or molecular compound.
Explanation:
Solutions are homogeneous mixtures formed by interaction between solutes and solvents.
Water based solutions have water as the solvents and mostly ionic and molecular compounds as their solutes.
Water is a polar solvent that is capable of dissolving many compounds by hydrating them. The molecules of water surrounds the solute and forces them to separate.
