55 m=180.446 ft.
7500/180.446= approx. 41.56 minutes
An electric current can be carried through a metal by the free flow of the shared electrons.
Answer:
7.35atm
Explanation:
Data obtained from the question include:
V1 = 28L
T1 = 42°C = 42 + 273 = 315K
P1 =?
V2 = 49L
T2 = 27°C = 27 + 273 = 300K
P2 = 4atm
Using P1V1/T1 = P2V2/T2, the original pressure can be obtained as follows:
P1V1/T1 = P2V2/T2
P1 x 28/315 = 4 x 49/300
Cross multiply to express in linear form
P1 x 28 x 300 = 315 x 4 x 49
Divide both side by 28 x 300
P1 = (315 x 4 x 49) /(28 x 300)
P1 = 7.35atm
Therefore, the original pressure is 7.35atm
