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2 years ago

Potassium

Chemistry

1 answer:

ad-work [718]2 years ago

4 0

Answer:

We observe that hydrogen burns at mouth of beaker with blue flame and pop sound is heard. It is a chemical change.

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a covalent bond forms a. when an element becomes a noble gas. b. when atoms share electrons. c. between metals and nonmetals. d.

marin [14]

(B)When atoms share electrons

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3 years ago

Write the ionization equation for hypochlorous acid, HClO, dissolved in water.

Pavel [41]

Answer:

HClO (l) → H⁺ (aq) + ClO⁻ (aq)

proton and hypochlorite.

Explanation:

HClO (Hypochlorous acid)

This is a weak acid that can be dissociated as this:

HClO (l) → H⁺ (aq) + ClO⁻ (aq)

proton and hypochlorite.

It is a weak acid, so it can adopt a Ka for its equilibrium

HClO + H₂O ⇄ H₃O⁺ + ClO⁻ Ka

Molar mass = 52.46 g/m

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3 years ago

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A if I’m not mistaking

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3 years ago

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8 0

3 years ago

A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside

Inessa05 [86]

<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

Initial volume, V1 = 100.0 mL
Initial temperature, T1 = 225°C, but K = °C + 273.15

thus, T1 = 498.15 K

Initial pressure, P1 = 1.80 atm
Final temperature , T2 = -25°C

= 248.15 K

Final pressure, P2 = 0.80 atm

We are required to calculate the new volume of the gases;

According to the combined gas law equation;

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

Rearranging the formula;

$V2=\frac{P1V1T2}{T1P2}$

Therefore;

$V2=\frac{(1.80atm)(100mL)(248.15K)}{(498.15K)(0.80atm)}$

$V2=112.08mL$

Therefore, the new volume of the gas is 112.08 mL

8 0

3 years ago