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lilavasa [31]
2 years ago
14

Potassium

Chemistry
1 answer:
ad-work [718]2 years ago
4 0

Answer:

  • We observe that hydrogen burns at mouth of beaker with blue flame and pop sound is heard. It is a chemical change.
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a covalent bond forms a. when an element becomes a noble gas. b. when atoms share electrons. c. between metals and nonmetals. d.
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(B)When atoms share electrons
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3 years ago
Write the ionization equation for hypochlorous acid, HClO, dissolved in water.
Pavel [41]

Answer:

HClO (l)  →  H⁺ (aq)    +       ClO⁻ (aq)

                 proton   and    hypochlorite.

Explanation:

HClO (Hypochlorous acid)

This is a weak acid that can be dissociated as this:

HClO (l)  →  H⁺ (aq)    +       ClO⁻ (aq)

                 proton   and    hypochlorite.

It is a weak acid, so it can adopt a Ka for its equilibrium

HClO +  H₂O  ⇄   H₃O⁺   +  ClO⁻          Ka

Molar mass = 52.46 g/m

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3 years ago
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3 years ago
A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside
Inessa05 [86]
<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

  • Initial volume, V1 = 100.0 mL
  • Initial temperature, T1 = 225°C, but K = °C + 273.15

thus, T1 = 498.15 K

  • Initial pressure, P1 = 1.80 atm
  • Final temperature , T2 = -25°C

                                     = 248.15 K

  • Final pressure, P2 = 0.80 atm

We are required to calculate the new volume of the gases;

  • According to the combined gas law equation;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

Rearranging the formula;

V2=\frac{P1V1T2}{T1P2}

Therefore;

V2=\frac{(1.80atm)(100mL)(248.15K)}{(498.15K)(0.80atm)}

V2=112.08mL

Therefore, the new volume of the gas is 112.08 mL

8 0
3 years ago
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