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CaHeK987 [17]
3 years ago
7

What is the gravitational constant g?

Physics
1 answer:
3241004551 [841]3 years ago
3 0

Answer: In SI units, G has the value 6.67 × 10-11 Newtons kg-2 m2. The direction of the force is in a straight line between the two bodies and is attractive. Thus, an apple falls from a tree because it feels the gravitational force of the Earth and is therefore subject to “gravity”.

Explanation:

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A 0 .1 kg pinball is fired horizontally by a springwith force constant 40 N/m. If the spring is depressed 10 cm and the ball col
ANEK [815]

Answer:

Explanation:

We can find out the velocity of pinball after being fired from the equation of conservation of mechanical energy

1/2 m v² = 1/2 k x² , m is mass of ball , v is velocity after firing , k is spring constant , x is depression in spring.

.1 x v² = 40 x .1 x .1

v = 2 m /s

ball of mass .1 , collides with velocity 2 m /s ,

from the equation of elastic collision

v₂ = (m₂ - m₁) u₁ / (m₂ + m₁) + 2m₁m₂u₂ / (m₂ + m₁)

m₁ ,u₁ are mass and velocity of first ball , m₂ , u₂ are mass and velocity of second mass , v₂ is velocity of second mass after collision.

u₁ = 2 , u₂ = 0 , m₁ = .1  m₂ = .3

v₂ = (.3 - .1 ) x 2/ (.3 + .1 )

= (.2 / .4 )x 2

= 1 m /s

So .3 kg ball will move with velocity of 1 m /s in the same direction as .1 m mass collided with it.

.

4 0
3 years ago
If the releases 39.4 kj of energy, how many kilocalories does it release? (1 cal = 4.184 j) (round off answer to 2 decimal place
REY [17]

By using unit conversion, the energy released in kilocalories is 9.42 kcal.

We need to know about unit conversion to solve this problem. There are several energy units which able to explain how much the energy is such as calories and joule. The energy unit can be converted to another unit by unit conversion. The unit conversion of calorie to joule is

1 cal = 4.184 joule

From the question above, we know that

E = 39.4 kJ

By using the unit conversion, we can convert the energy into calorie

E = 39.4 kJ

E = 39.4 x 10³ J

E = 39.4 x 10³ / 4.184 cal

E = 9.42 x 10³ cal

E = 9.42 x 10³ /10³  kcal

E = 9.42 kcal

Hence, the energy released in kilocalories is 9.42 kcal.

Find more on unit conversion at: brainly.com/question/141163

#SPJ4

8 0
2 years ago
Assume that a friend hands you a 10-newton box to hold for her. If you hold the box without moving it at a height of 10 meters a
malfutka [58]

Answer:

100 Joules

Explanation:

Applying,

W = mgh................... Equation 1

Where W = workdone to hold the box above the ground, mg = weight of the box, h = height of the box.

From the question,

Given: mg = 10 newtons, h = 10 meters.

Substitute these values into equation 1

W = 10×10

W = 100 Joules.

Hence the amount of workdone is 100 Joules

7 0
3 years ago
Momentum is mass times .
anzhelika [568]

Answer:True

Explanation:

4 0
3 years ago
Read 2 more answers
A plane flies 446 km east from city A to city B in 43.0 min and then 939 km south from city B to city C in 1.10 h. For the total
NeTakaya

Answer:

(a) Magnitude is 1039 km

(b) Direction of the displacement is 64.59^{\circ} South of East

(c) Average velocity magnitude is 570.88 km

(d) The direction of average velocity is 64.59^{\circ} South of East

(e) Average speed is 759.34 km/h

Solution:

Distance moved from A to B in East direction, \vec{AB} = 446 km

Distance moved from B to C in South direction, \vec{BC} = - 939 km

Time taken to move from A to B, t = 43.0 min = 0.72 h

Time taken to move from B to C, t' = 1.10 h

Now,

(a) The magnitude of displacement of the plane is provided by AC as shown in fig 1 and can be given as:

AC = \sqrt{(AB)^{2} + (BC)^{2}}

AC = \sqrt{(446)^{2} + (- 939)^{2}} = 1039 km

(b) Direction of the displacement is given by:

tan\theta = \frac{\vec{BC}}{\vec{AB}}

\theta = tan^{- 1}(\frac{- 939}{\vec{446}}) = - 64.59^{\circ}

64.59^{\circ} South of East

(c) Magnitude of the average speed is given by:

v_{avg} = \frac{AC}{t + t'}

v_{avg} = \frac{1039}{1.82} = 570.88 km/h

(d) The direction of the average velocity is the same as that of the displacement, i.e., 64.59^{\circ} South of East.

(e) The average speed of the [plane is given by:

v'_{avg} = \frac{Total\ Distance\ Traveled}{Total\ Time}

v'_{avg} = \frac{446 + 939}{1.10 + 0.72} = 759.34 km/h

6 0
3 years ago
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