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cestrela7 [59]
3 years ago
7

A 0 .1 kg pinball is fired horizontally by a springwith force constant 40 N/m. If the spring is depressed 10 cm and the ball col

lides with a 0.3 kg ball elastically, what is the post collision velocity of the 0.3 kg ball? *
Physics
1 answer:
ANEK [815]3 years ago
4 0

Answer:

Explanation:

We can find out the velocity of pinball after being fired from the equation of conservation of mechanical energy

1/2 m v² = 1/2 k x² , m is mass of ball , v is velocity after firing , k is spring constant , x is depression in spring.

.1 x v² = 40 x .1 x .1

v = 2 m /s

ball of mass .1 , collides with velocity 2 m /s ,

from the equation of elastic collision

v₂ = (m₂ - m₁) u₁ / (m₂ + m₁) + 2m₁m₂u₂ / (m₂ + m₁)

m₁ ,u₁ are mass and velocity of first ball , m₂ , u₂ are mass and velocity of second mass , v₂ is velocity of second mass after collision.

u₁ = 2 , u₂ = 0 , m₁ = .1  m₂ = .3

v₂ = (.3 - .1 ) x 2/ (.3 + .1 )

= (.2 / .4 )x 2

= 1 m /s

So .3 kg ball will move with velocity of 1 m /s in the same direction as .1 m mass collided with it.

.

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A person stands between two speakers driven by the same source. Each speaker produces a tone with a frequency of 200 Hz on a day
MissTica

Answer:

The type of interference the person perceives is a Constructive Interference

Explanation:

Before we solve the problem we need to clarify some concepts:  

There are two types of Interference, the Constructive and the Destructive interference  

The Constructive Interference happens if the difference between the waves movement is equal to an even semi-wavelength number

The Destructive Interference is the opposite than the Constructive Interference, it happens if the difference between the waves movement is equal to an odd semi-wavelength number

Taking the above into account let´s proceed to solve the problem.

First, we will need to find how much the wavelength is (we will call it l), we know the frequency f=200Hz, we also know the speed of sound is v=330m/s. We will use the next equation:

l=v/f then we get that l=1.65m

In order to find the semi-wavelength we must divide by 2 the previous result, in this case the semi-wavelength will be:  

l/2=0.825m

Now, we find the difference between the waves movement, which is the difference between both distances, this difference will be called d and we will find it this way:

d=4.95m-1.65m then d=3.3m

After this, we will do a relation between the distance and the semi-wavelength in order to find what type of interference the person perceives, this way:

(d)/(l/2) then, we have a relation equals to 4. As it´s an even number, we determine the interference is a Constructive Interference

8 0
4 years ago
Sitting in a second-story apartment, a physicist notices a ball moving straight upward just outside her window. The ball is visi
gregori [183]

Answer:

1.013 s

Explanation:

You  can solve this problem using the equations for constant acceleration motion. The velocity at the bottom of the window can be found using this expression:

(x-x_o) = \frac{1}{2} at^2 + v_ot = -\frac{1}{2}gt^2 + v_ot

the gravity is negative as it opposes the movement.

(x-x_o) = -\frac{1}{2}gt^2 + v_ot\\v_o = \frac{(x-x_o)+\frac{1}{2}gt^2}{t} = \frac{1.19m+\frac{1}{2} 9.81m/s^2(0.2s)^2}{0.2s} = 6.931 m/s

Now, the time elapsed before the ball reappears is 2 times the time that it takes for the ball to go from the bottom of the window, reach maximum height, and reach again the bottom of the window, minus 2 times the time that it takes for the ball to travel from the top to the bottom of the window. The time that takes to the ball to reach maximum height, or in other words, to time that takes for the velocity of the ball to go from vo to 0m/s:

t_1 = \frac{0m/s - v_o}{g}  = \frac{-6.931 m/s}{-9.81m/s^2} = 0.706 s

Then:

t = 2t_1 - 2*0.2s = 2*(0.706s) - 0.4s = 1.013 s

7 0
3 years ago
A person of Mass 50kg is on a swing which has the speed 10m,/s at the lowest point of the motion the ropes of the swing are 2.5m
atroni [7]

Answer:

T  =  2490 newton

Explanation:

Given that,

Mass of a person, m = 50 Kg

Speed of the swing at the lowest point, v = 10 m/s

Length of the rope, r = 2.5 m

Tension formula is given by

                            T = mg + ma  N

where,              T - Tension in the string

                         m - mass of the body

                         g - acceleration due to gravity

                          a - acceleration of the body

Since the person is swinging, the acceleration of the body is given by

                          a = v²/r m/s²

                             = 10/2.5  m/s²

                          a = 40 m/s²

Substituting in T

                   T  =  50 Kg x 9.8 m/s²  + 50 Kg X 40 m/s²

                       = 490 + 2000 Kg m/s²

                   T  =  2490 newton

Therefore the tension in the rope is 2490 newton

8 0
4 years ago
A stone is dropped from the edge of a roof. find the distance travelled by the stone in 2sec after its release.
Lena [83]
S = ?
U = 0
V = ?
A = 9.81
T = 2

we tryna find s

lets use s = ut + (at^2)/2
ut cancels out since u = 0
(at^2)/2 = (9.81 x 2^2)/2
= 19.62m
3 0
3 years ago
(can someone please help me with these 4 papers do tomorrow and I just can't seem to understand "Newton's law")
gladu [14]
Hi!

1) Newton's first law (Inertia). The body wil keep moving on the same speed of the car.

2) Newton's second law. F = ma

3) Newton's third law.

4) Law of conservation of momentum
5 0
4 years ago
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