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nekit [7.7K]
3 years ago
12

Assume that a friend hands you a 10-newton box to hold for her. If you hold the box without moving it at a height of 10 meters a

bove the ground, how much work do you do
Physics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

100 Joules

Explanation:

Applying,

W = mgh................... Equation 1

Where W = workdone to hold the box above the ground, mg = weight of the box, h = height of the box.

From the question,

Given: mg = 10 newtons, h = 10 meters.

Substitute these values into equation 1

W = 10×10

W = 100 Joules.

Hence the amount of workdone is 100 Joules

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Which statement correctly describes the quantitative relationship between acceleration and net force on an object shown in the d
Brrunno [24]

Answer:

The correct answer is A

Explanation:

<h2><u>Because when the net force applied to an object changes, the acceleration changes by the same factor.  This answer is correct and I hope it helps you too.</u></h2><h2><u></u></h2>

Hope this helps....

Have a nice day!!!!

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7 0
3 years ago
The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an
Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

   \Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t

or,      \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

Putting the given values into the above formula as follows.

    \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

                = \frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}    

                = 0.326 rad/s^{2}

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 rad/s^{2}.

5 0
4 years ago
A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio
vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

F= qVB

Replacing

F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})

F=9.36*10^{-19}

c) Given the second Newton's Law by

F_g = 1.67*10^{-27}*9.81

F_g = 1.64*10^{-26}

Given the electric force by,

F_e = 1.6*10^{-19}*1.5*10^2

F_e = 2.4*10^{-17}N

F=9.36*10^{-19}N

7 0
3 years ago
A rock is thrown vertically upward from the origin of a reference frame. The rock reaches the peak of its trajectory and then it
Tema [17]

Answer:

The acceleration of the rock is negative throughout the whole motion. (TRUE)

The acceleration of the rock is zero at the peak of the trajectory (FALSE)

The velocity of the rock is positive throughout the whole motion (FALSE)

The position of the rock is positive or zero throughout the whole motion (TRUE)

The velocity of the rock is positive throughout the whole motion (FALSE)

Explanation:

1)The acceleration of the rock is negative throughout the whole motion. (TRUE)

Using the upward direction as positive

Then, The acceleration of the rock is negative throughout the whole motion.

2)The acceleration of the rock is zero at the peak of the trajectory.(FALSE)

Only the velocity can be zero at the peak the trajectory, the acceleration is not zero

3)The velocity of the rock is positive throughout the whole motion (FALSE)

Using the upward direction as positive, The velocity of the rock is only positive when going in upward direction and vice versa

4)The position of the rock is positive or zero throughout the whole motion (TRUE)

When the rock get down it will have a zero position, then when it get to the peak it will have positive position

6 0
4 years ago
Other than the weather, what force wears down the new rock formed by the magma from Kilauea?
gtnhenbr [62]
People can break down the rock by touching or the heat can even break down the rock
7 0
3 years ago
Read 2 more answers
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