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SVETLANKA909090 [29]
4 years ago
5

Standing on the surface of the Earth you drop a rock down a well and it falls for 5 seconds before hitting the bottom. How fast

is it moving when it hits the bottom of the well
Physics
2 answers:
lbvjy [14]4 years ago
5 0

Answer:

it was moving at 50m/s when it hits the well bottom

Explanation:

Using Newton first law of motion;

V=u+gt

v=final velocity (what we are about to calculate)

u=initial velocity which is 0

g= acceleration due to gravity 10m/s^2(since its expressing free fall it will be       positive)

t=time taken 5seconds

v=0+10(5)

v=50m/s

strojnjashka [21]4 years ago
3 0

Answer:

49 m/s.

Explanation:

Given:

Time, t = 5 s

Vo = 0 m/s

a = 9.8 m/s2

Using equations of motion,

Vf = Vo + at

Vf = 0 + 9.8 × 5

= 49 m/s.

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NHT0015
poizon [28]

Answer:

(1) 1×10⁻⁴

Explanation:

From the question,

α = (ΔL/L)/(ΔT)............. Equation 1

Where α = linear expansivity of the metal plate, ΔL/L = Fractional change in Length, ΔT = Rise in temperature.

Given: ΔL/L = 1×10⁻⁴, ΔT = 10°C

Substitute these values into equation 1

α  = 1×10⁻⁴/10

α = 1×10⁻⁵ °C⁻¹ .

β = (ΔA/A)/ΔT................... Equation 2

Where β = Coefficient of Area expansivity, ΔA/A = Fractional change in area.

make ΔA/A the subject of the equation

ΔA/A = β×ΔT.......................... Equation 3

But,

β = 2α.......................... Equation 4

Substitute equation 4 into equation 3

ΔA/A = 2α×ΔT................ Equation 5

Given: ΔT = 5°C, α = 1×10⁻⁵ °C⁻¹

Substitute into equation 5

ΔA/A = ( 2)×(1×10⁻⁵)×(5)

ΔA/A  = 10×10⁻⁵

ΔA/A  = 1×10⁻⁴

Hence the right option is (1) 1×10⁻⁴

3 0
3 years ago
5. Find the volume of the composite space figure to the nearest whole number.
Dmitry [639]
The shape is missing but let's consider it a semi-cylinder attached to the rectangular prism.
Given:
radius = 4.5 mm 
<span>Height = 11 mm </span>

<span>Volume of cylinder = (1/2)(pi)(4.5)^2(11)   (the shape is divided into half)
                           V = 349.89 mm cubed
Volume of prism = L x W x H
                           = 9 x 11 x 6
                           = 594 mm cubed
Total volume of the composite shape = 111.375 + 594 
                                                            = 943.89 mm cubed
Rounded answer = 944 mm cubed.</span>
6 0
4 years ago
A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and
iogann1982 [59]

Answer:

p_2 = 1.76 atm

Explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}

Putting the values

\frac{1.15*2.37}{280}  =\frac{p_2 *1.68}{304}

9.733*10^{-3} = \frac{p_2 *1.68}{304}

9.733*10^{-3}*304 = p_2*1.68

\frac{9.733*10^{-3}*304}{1.68} =p_2

p_2= 1.76 atm

7 0
4 years ago
How can the density of an object be determined?”
Nastasia [14]

Answer:

First you need to know the mass (grams) of the object and its volume, then what you do is  Divide the mass by the volume in order to get an object's Density.

Explanation:

hope that helped good luck :)

6 0
4 years ago
Read 2 more answers
Find the gravitational force that Earth (mass = 5.97 × 10²⁴ kg) exerts on the moon (mass = 7.35 × 10²² kg) when the distance bet
alexandr402 [8]

Explanation:

mass of earth (m1)=5.97×10^24

mass of moon (m2)=7.35×10^22

distance between their center (d)= 3.84×10^8

G=6.67×10^-11

now,

gravitational force =(F)= G(m1×m2)/d²

  • 6.67×10^-11(5.97×10^24×7.35×10^22)/(3.84×10^8)
  • 19.84×10^19

<h3>stay safe healthy and happy...</h3>
3 0
3 years ago
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