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andre [41]
3 years ago
9

Specific data such as age, income, family size, and occupation, used for marketing purposes, is called

Physics
2 answers:
True [87]3 years ago
5 0
<span>B. demographics.

</span>Specific data such as age, income, family size, and occupation, used for marketing purposes, is called demographics.
NOT:
A. a secondary market.
C. survey statistics.
<span>D. the target market.</span>
djyliett [7]3 years ago
3 0
<h3><u>Answer;</u></h3>

B. demographics.

Specific data such as age, income, family size, and occupation, used for marketing purposes, is called  <em><u>demographics.</u></em>

<h3><u>Explanation;</u></h3>
  • <em><u>Demographics are features of a particular population. It involves the study of a population based on factors such as age, sex, race, family size and occupation, etc.</u></em>
  • <em><u>For marketing purposes firms or companies use specific data such as age, income, family size, religion, race, nationality and occupation. </u></em><em><u>This may be referred to as demographic segmentation, which is used by the companies to get the right population using their products. </u></em>
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6 0
3 years ago
A 20-kg child starts at the center of a playground merry-go-round that has a radius of 1.5 mm and rotational inertia of 500kg⋅m2
Lemur [1.5K]

Answer:

w = 0.189 rad/ s

Explanation:

This exercise we work with the conservation of the moment, the system is made up of the merry-go-round and the child, for which we write the moment of two instants

Initial

         L₀ = I₀ w₀

Final

          L_{f} = I w

         L₀ = L_{f}

         I₀ w₀ = I_{f} w

         .w = I₀/I_{f}   w₀

The initial moment of inertia is

        I₀ = 500 kg. m2

The final moment of inertia

         I_{f} = 500 + m r²

         I_{f} = 500 + 20 1.5

         I_{f} = 530 kg m²

Initial angular velocity

         w₀ = 0.20 rad / s

Let's calculate

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6 0
3 years ago
A spider spins a web with silk threads of density 1300 kg/m3 and diameter 3.0 μm . a typical tension in the radial threads of su
Tema [17]

Answer:

Explanation:

The velocity of a wave in a string is equal to:

v = √(T / (m/L))

where T is the tension and m/L is the mass per length.

To find the mass per length, we need to find the cross-sectional area of the thread.

A = πr² = π/4 d²

A = π (3.0×10⁻⁶ m)²

A = 2.83×10⁻¹¹ m²

So the mass per length is:

m/L = ρA

m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)

m/L = 3.68×10⁻⁸ kg/m

So the wave velocity is:

v = √(T / (m/L))

v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))

v ≈ 440 m/s

The speed of sound in air at sea level is around 340 m/s.  So the spider will feel the vibration in the thread before it hears the sound.

5 0
3 years ago
A mass is set oscillating horizontally, with an amplitude of 11.3 cm and a period of 0.702 sec. What is the velocity of the part
Zinaida [17]

Answer:

Explanation:

18.1

6 0
3 years ago
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