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tatyana61 [14]
3 years ago
9

STUCK ON THESE!!! PLEASE HELP!

Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

_20___ × (-1/2) × __2__ = -20

8 x (-1/2) x 5= -20

Step-by-step explanation:

Hope I helped

DIA [1.3K]3 years ago
3 0
-80 , 1/2 is the answer
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Find the coordinates of the point of intersection of all parabolas that have equation y=x2+px +q with p+q=2020. The point of int
ioda

Answer:

(1,2021)

Step-by-step explanation:

P and q can vary subject to their sum being 2020.

Consider one parabola with p1 and q1 and another with p2 and q2.

y1=(x1)^2+(p1)(x1)+(q1)

y1=(x2)^2+(p2)(x2)+(q2)

At their intersection, the x and y coordinates are the same.

y1=y2=y

x1=x2=x

x^2+(p1)x+(q1)=x^2+(p2)x+(q2)

Solve for x

x(p1-p2)=q2-q1

x=(q2-q1)/(p1-p2)

Use the constraint that p+q=2020 to eliminate p1 and p2.

p1=2020-q1

p2=2020-q2

x=(q2-q1)/(2020-q1-2020+q2)

x=(q2-q1)/(q2-q1)

x=1

Substitute in the equation for y.

y=1^2+p(1)+q

y=2021

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3 years ago
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