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DerKrebs [107]
3 years ago
8

A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose fr

om. Different platters can be created by changing the size and/or the choice of vegetables. If Selena wants to order a platter with exactly 2 different vegetables, how many different platters could she create?
Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer: She could create 60 platters.

Step-by-step explanation:

Given: A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose from.

Number of combinations of selecting <em>r</em> things from <em>n</em> things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

So, the number of combinations of selecting 2 different vegetables from 6 = ^6C_2=\dfrac{6!}{2!4!}=\dfrac{6\times5}{2}=15

Now, By Fundamental counting principle, the number of different platters she could create = (number of ways of selecting 2 different vegetables from 6) x (Number of sizes)

= 15 x 4

= 60

Hence, she could create 60 platters.

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Both rooms share a common side whose dimension is unknown. Call it x.

Then, the area of both squares have x as common factor.

So, x is the greatest common factor of 104 and 130.

You should know how to calculate the greatest common factor of two integers.

Just find the prime factors and choose the common factors raised to the lowest exponent.

104 = (2^3) (13)

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=> the greatest common factor is 2 * 13 = 26, and that is the greatest possible integer length of the shared wall.

Answer: 26



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