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Diano4ka-milaya [45]
3 years ago
9

Suppose () = 1/8 for 0 ≤ ≤ 4 for x being a continuous random variable Is () a probability density function? Prove or disprove.

Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

The expected value of x ; E(x) = 1

Step-by-step explanation:

F(x) = 1/8 for 0 ≤ x ≤ 4

To prove that it is a probability density function we will find E(x )

attached below is the required prove

It is proven that F(x) = 1/8 for 0 ≤ x ≤ 4 is  probability density function

The expected value of X = 1

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The price that a company charged for a computer accessory is given by the equation 100-x^2 where x is the number of accessories
Setler79 [48]

Answer:

1.45 million accessories

Step-by-step explanation:

we need to write an algebraic equation

y = (100 - 10x^2)x - 10x

y represents the profit

x represents the # of accesories produced in millions

I used 10 because that's the cost of making each accessory

100-x^2=consumer price

x-10x= accessory-cost to make all the accessories

we know that 2 million accessories make 100 million

so the number of accessories that approximately make 100 should be around 2 million

in the options 1.45 is given which is close to 2

even though 3.45 is closer than two you would go beyond a 100 million profit which isn't what you want

if the options weren't given you would have to use all values from 1-2 as "x"

hope this helps!

6 0
4 years ago
Read 2 more answers
PLEASE HELP!! 30 POINT!
KIM [24]

Answer:

(E) 3(sq rt 2)

Step-by-step explanation:

the figure is a square so all four sides are equal and has 90 degree corners.

the diagonal has the value of 6 so:

6^2=s^2+s^2

36=2s^2

s^2=18  or sq rt 18 which would be 3(sq rt 2)

5 0
3 years ago
Expand (a+b)^7 using pascal triangle
Inga [223]

(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7

8 0
3 years ago
E is the midpoint of DF⎯⎯⎯⎯⎯, DE=6x+1 and EF=7x−4. Find DE, EF, and DF
grandymaker [24]

DE is 31 units, EF is 31 units and DF is 62 units

Step-by-step explanation:

A mid-point of a line segment

  • Divides it into two congruent parts
  • The length of each part is half the length of the line segment

∵ E is the mid-point of segment DF

- That means E divides DF into two parts DE and EF and the

   lengths of them are equal

∴ DE ≅ EF

∵ DE = 6x + 1

∵ EF = 7x - 4

- Equate them

∴ 6x + 1 = 7x - 4

- Add 4 to both sides

∴ 6x + 5 = 7x

- Subtract 6x from both sides

∴ 5 = x

Substitute the value of x in DE and EF to find their length

∵ DE = 6(5) + 1

∵ DE = 30 + 1

∴ DE = 31 units

∵ EF = 7(5) - 4

∴ EF = 35 - 4

∴ EF = 31 units

∵ DF = DE + EF

∴ DF = 31 + 31

∴ DF = 62 units

DE is 31 units, EF is 31 units and DF is 62 units

Learn more:

You can learn more about the mid-point in brainly.com/question/10480770

#LearnwithBrainly

8 0
3 years ago
I need some math help
Kobotan [32]
This is an answer should help you
8 0
3 years ago
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