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Diano4ka-milaya [45]
3 years ago
9

Suppose () = 1/8 for 0 ≤ ≤ 4 for x being a continuous random variable Is () a probability density function? Prove or disprove.

Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

The expected value of x ; E(x) = 1

Step-by-step explanation:

F(x) = 1/8 for 0 ≤ x ≤ 4

To prove that it is a probability density function we will find E(x )

attached below is the required prove

It is proven that F(x) = 1/8 for 0 ≤ x ≤ 4 is  probability density function

The expected value of X = 1

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The table represents a function.
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f(5) is -8 ⇒ 1st answer

Step-by-step explanation:

Function is a relation between set of of ordered pairs (x , y),and every x has only one y

Examples:

  • {(-1 , 2) , (2 , 4) , (5 , -3)} is a function because x = -1 has only y = 2, x = 2 has only y = 4 and x = 5 has only y = -3
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The notation of the function is f(x) = y

The table:

→    x     :    f(x)

→    -4    :    -2

→    -1     :    5

→     3    :    4

→     5    :   -8

From the table

∵ x = -4

- The corresponding value of y to x = -4 is -2

∴ f(-4) = -2

∵ x = -1

- The corresponding value of y to x = -1 is 5

∴ f(-1) = 5

∵ x = 3

- The corresponding value of y to x = 3 is 4

∴ f(3) = 4

∵ x = 5

- The corresponding value of y to x = 5 is -8

∴ f(5) =-8

f(5) is -8

Learn more:

You can learn more about the functions in brainly.com/question/10879401

#LearnwithBrainly

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Answer:

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