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aivan3 [116]
2 years ago
5

Which of the following is a correct interpretation of the expression - 6 + 9?

Mathematics
2 answers:
Maru [420]2 years ago
8 0

Answer:

-3

Step-by-step explanation:

Andreyy892 years ago
4 0

Answer:

It’s basically 3.

Step-by-step explanation:

Just subtract 9 - 6 which gets you a 3 since there’s a negative sign.

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The number 8,046 can be modeled using base ten blocks. How many of each type of block are needed to build the number?
MArishka [77]

Answer:

the first one

Step-by-step explanation:

8 one thousand block is 8000

0 hundreds 000

4 tens. 40

6 ones. 6

8046

7 0
2 years ago
Read 2 more answers
Graph quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3) and its image after the translation (x,y)→(x−5,y−2)
maria [59]

The graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners.

We have:

Quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3)

We can graph it on the coordinate plane as shown in the picture.

After applying the translation (x, y)→(x−5, y−2), the points becomes:

A'(-3, -5)

B'(-2, 3)

C'(1, 4)

D'(0, -5)

Similarly, we can graph it on the coordinate plane (refer attached picture)

Thus, the graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)

Learn more about the quadrilateral here:

brainly.com/question/6321910

#SPJ1

6 0
2 years ago
Can someone please help me with this math problem.
mr Goodwill [35]
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20

d for P₂ = 76 - 82
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20

d for P₂ = 70 - 76
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40

d for P₂ = 70 - 82
d for P₂ = -12

The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
4 0
3 years ago
How do you get the same base for the power
rewona [7]
You use division

over 2 or 4 or 3 or 5 or 7 and so on
in this case 2 is good

64 = 2 * 2 * 2 * 2 * 2 * 2 ( use division) = 2^6

16 = 2 * 2 * 2 * 2 = 2^4

number reminder
64 0
32 0
16 0
8    0
4   0
2   0
1   1

so 64 = 2^6 (number of zeros) no reminder


3 0
3 years ago
Make 24 using the numbers 1,6,8,8 be sure to use all four operations
nignag [31]

6/1=6x1=6

8+8=16+6

22+2

24

3 0
3 years ago
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