Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
Option 3
Step-by-step explanation: I think it is option 3
Answer:
<u>9 mph</u>
Step-by-step explanation:
Calvin's first leg of the trip took 0.5 hr (30 minutes) at 6 mph. That means he travelled (0.5hr x 6 mph =) 3 miles. He travelled 3 miles on the return trip, by definition (same path home). At 18 mph, 3 miles would take (3 miles/18 mph =) 0.1667 hours. That makes a total of 6 miles and (0.5 + 0.1667=) 0.6667 hours.
(6 miles)/(0.6667 hours) = 9 mph is Calvin's average speed for the round trip.
Answer:
Bank of Texas = $10,031.35
United Texas Bank = $10,500.00
Step-by-step explanation:
Bank of Texas
A=P(1+rt)
P=$7,500
r=6.75%
t=5 years
$10,031.35
refer the pic
United Texas Bank
A=P(1+rt)
P=$7,500
r=8%
t=5 years
$10,500.00
refer the sec pic