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LuckyWell [14K]
3 years ago
11

Let f (x) = -1/2(x + 2)+ 5

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

Rate of change = -1

Step-by-step explanation:

Given:

f(x) = -½(x + 2)² + 5

Required:

Average rate of change from x = -3 to x = 1

Solution:

Rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = -3,

f(a) = f(-3) = -½(-3 + 2)² + 5 = -½(-1)² + 5 = 4.5

b = 1,

f(b) = f(1) = -½(1 + 2)² + 5 = -½(9) + 5 = 0.5

Plug in the values into the formula:

Rate of change = \frac{0.5 - 4.5}{1 - (-3)}

Rate of change = \frac{-4}{4}

Rate of change = -1

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Hence the domain in the given relation {(-6, 3), (-4 ,5), (0, 0) is :

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Step-by-step explanation:

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2 years ago
Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84
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Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

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expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

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subtract 84 on both sides to bring it to the left:

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factorise out x:

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using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

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the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

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add 10 on both sides

20k = 10 and 20k = 10

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