All categories

3 years ago

Help me find the radius or just help with the riddle at the bottom

Mathematics

2 answers:

Kay [80]3 years ago

7 0

The answer to the riddle is: it has the edge.

Rina8888 [55]3 years ago

5 0

Hi! Could you possibly get a clearer picture? If not I can try my hardest to figure it out

You might be interested in

A rectangular piece of land has an area of 3/4 square mile. The land is 21/2 mile. What is its width

OleMash [197]

Answer:

The width of the rectangle is $\frac{1}{14}$ miles

Step-by-step explanation:

Given as for rectangle

The area of rectangle = A = $\frac{3}{4}$ mile²

The Length of rectangle = L = $\frac{21}{2}$ mile

Let The width of rectangle = W miles

Now, From area of rectangle

I.e Area of Rectangle = Length × Width

Or , A = $\frac{21}{2}$ mile × W mile

Or, $\frac{3}{4}$ mile² = $\frac{21}{2}$ mile × W mile

or, W = $\frac{\frac{3}{4}}{\frac{21}{2}}$ mile

or, W = $\frac{3\times 2}{4\times 21}$

∴ W = $\frac{1}{14}$ miles

Hence The width of the rectangle is $\frac{1}{14}$ miles Answer

4 0

3 years ago

Find the sum. 2/5(d-10)-2/3(d+6)

alukav5142 [94]

Answer:

-4d

Step-by-step explanation:

L.c.m=15

15×2/5(d-10)-2/3×15(d+6)

3×2(d-10)-2×5(d+6)

6(d-10)-10(d+6)

6d-60-10d-60

6d-10d-60-60

-4d-0

-4d

5 0

2 years ago

Please guys help me qith this i will brainlist u i promise

valkas [14]

Answer:

1. 3,085,003

2. 114,000,726

3. 7,098,000

4. 882,108

5. 500,006,719

Step-by-step explanation:

3 0

2 years ago

How do you find the pattern of 0,2,6,12,20???

professor190 [17]

0x1=0
1x2=2
2x3=6
3x4=12
4x5=20

3 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago