<h2>
Answer:</h2>
a. <-13/2,-13/2>
<h2>
Step-by-step explanation:</h2>
The projection of a vector u onto another vector v is given by;
= 
----------------(i)
Where;
u.v is the dot product of vectors u and v
|v| is the magnitude of vector v
Given:
u = <-6, -7>
v = <1, 1>
These can be re-written in unit vector notation as;
u = -6i -7j
v = i + j
<em>Now;</em>
<em>Let's find the following</em>
(i) u . v
u . v = (-6i - 7j) . (i + j)
u . v = (-6i) (1i) + (-7j)(1j) [Remember that, i.i = j.j = 1]
u . v = -6 -7 = -13
(ii) |v|
|v| = 
|v| = 
<em>Substitute these values into equation (i) as follows;</em>
= ![[\frac{-13}{(\sqrt{2}) ^2}][i + j]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B-13%7D%7B%28%5Csqrt%7B2%7D%29%20%5E2%7D%5D%5Bi%20%2B%20j%5D)
= ![\frac{-13}{2} [i + j]](https://tex.z-dn.net/?f=%5Cfrac%7B-13%7D%7B2%7D%20%5Bi%20%2B%20j%5D)
This can be re-written as;
= 
= 
Answer:b
Step-by-step explanation:
Answer:
y=x+w/5
Step-by-step explanation:
x=5y-w
step 1: bring the additional letters/numbers next to the "5y" over to the left
x+w= 5y
step 2: divide the numbers and letters on both sides of the "=" by 5 to only get the letter y
x+w/5= y
step 3: swap them over
y= x+w/5
(we can't get an answer from x+w/5 because the terms are unlike, therefore we keep it as a fraction
Answer:
B. TRUE.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
Step-by-step explanation:
Option B is TRUE because intersection point should satisfy both the equation
and in option be it comes true.
i.e x = 3 and y = 2 we have
3 + 2 = 5 and 3 - 2 = 1
5 = 5 and 1 = 1
Hence TRUE
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 3 and y = 2 we have
3×3 + 2×2 = 5 and 3×3 - 2×2 = 1
13 ≠ 5 and 5 ≠ 1
Hence FALSE
C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 5 and y = 1 we have
3×5 + 2×3 = 5 and 3×5 - 2×3 = 1
21 ≠ 5 and 9 ≠ 1
Hence FALSE
D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
i.e x = 5 and y = 1 we have
5 + 1 = 5 and 5 - 1 = 1
6 ≠ 5 and 4 ≠ 1
Hence FALSE
Answer:
The answer would be that All the powers have a value if 1 because the exponent is zero.
Step-by-step explanation:
Use the exponent rule to help you
